Explanation 1) Concept: Using Eq.36-29, we can find differential equation for dispersion. Differentiating Eq.36-25 with respect to λ and substituting the equation for m from Eq.36-25, we can prove that the dispersion of grating is D = t a n θ / λ . 2) Formula: i) From Eq. 36 - 29 , the dispersion is given by D = ∆ θ ∆ λ ii) From Eq. 36 - 25 , the condition for diffraction grating is d s i n θ = m λ 3) Given: D is the dispersion of grating. 4) Calculations: From Eq. 36 - 29 , the dispersion is given by D = ∆ θ ∆ λ Therefore, for diffraction grating, the dispersion is D = d θ d λ … … … … … … … … … … … … … … … … … … … … … … … ( 1 ) From Eq

10th Edition

ISBN: 9781118230725

Author: David Halliday, Robert Resnick, Jearl Walker

Publisher: Wiley, John & Sons, Incorporated

See similar textbooks

Concept explainers

Electromagnetic Waves

Electromagnetic waves are waves that consist of magnetic field and electric field components perpendicular to each other. These field components are also perpendicular to the direction of propagation of the wave.

Question

Chapter 36, Problem 101P

To determine

To show:

Dispersion of grating is D=tan⁡θ/λ

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 36, Problem 100P

Chapter 36, Problem 102P

Students have asked these similar questions

12.20 Show that the Fourier series for |sinθ| in the range –π < 0 < π is given by M8 Σ | sin 0| m=1 1 = 4m2 2 By setting 0 = 0 and 0 = π /2, deduce values for 1 π 4 π ∞0 and m=1 cos 2mθ 4m2 – 1 ∞o Σ m=1 1 16m2 – 1

OTS tutorial (a) Explain the origin of the transverse phase condition that results in the equation for a slab waveguide given below (b) (c) (d) (1) 2nd√/n²-n² 20 = mл+Sp Explain what happens if this condition is not satisfied? Ignoring the G-H shift term, rearrange this equation for n For a waveguide at a wavelength of 1.55um, a core index of 3.5 and a thickness of 2um, work out the effective indices for m= 1, 2, 3 and 4 What happens to the modal index as the m number increases? Why? Explain why the mode effective index for the m-1 is not 3.5

Chapter 36 Solutions

Fundamentals of Physics Extended

Ch. 36 - You are conducting a single-slit diffraction...Ch. 36 - In a single-slit diffraction experiment, the top...Ch. 36 - For three experiments, Fig. 36-30 gives the...Ch. 36 - For three experiments, Fig. 36-31 gives versus...Ch. 36 - Figure 36-32 shows four choices for the...Ch. 36 - Prob. 6Q Ch. 36 - At night many people see rings called entoptic...Ch. 36 - a For a given diffraction grating, does the...Ch. 36 - Figure 36-33 shows a red line and a green line of...Ch. 36 - For the situation of Question 9 and Fig. 36-33, if...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Dispersion of grating is D = tan ⁡ θ / λ

Solution Summary: The author explains that the dispersion of grating is D=(mathrmtantheta )/lambda .

Concept explainers

To show:

Dispersion of grating is D=tan⁡θ/λ

Want to see the full answer?

Chapter 36 Solutions

Dispersion of grating is D = tan ⁡ θ / λ

Solution Summary: The author explains that the dispersion of grating is D=(mathrmtantheta )/lambda .

Concept explainers

To show: Dispersion of grating is D=tan⁡θ/λ

Want to see the full answer?

Chapter 36 Solutions

To show:

Dispersion of grating is D=tan⁡θ/λ