
a)
To find: system of inequalities to represent the given situations.
a)

Explanation of Solution
Given Information
Let, ‘ c’ be the number of chairs and ‘ t’ be the number of tables
According to question,
Carpentry and finishing time per chair is 3 hrs and 0.5 hr respectively and for table it is 2 hrs and 1 hr respectively.
Formula Used for Graph
where, ‘ c’ and ‘ b’ are x and y intercepts respectively.
Calculation Maximum carpentry time is 108 hours
So,
and, maximum finishing time is 20 hours
So,
Now, we will plot equation (i) and (ii) graphically, to find out the feasible region and also calculate the maximum profit.
For plotting the graph, we will simplify the equations as:
⇒
⇒
This equation is of the form,
where, ‘ c’ and ‘ b’ are x and y intercepts respectively.
Now,
Now we will plot equations (iii) and (iv) graphically.
b)
To draw: showing the feasible region
b)

Explanation of Solution
Graph
c)
To find: required number of tables and chairs to maximize the profit and maximum profit.
c)

Answer to Problem 15E
Maximum Profit = $1265
Explanation of Solution
Given Information
Let, ‘ c’ be the number of chairs and ‘t’ be the number of tables
Point ‘ P’ represents the required number of tables and chairs to maximize the profit.
On solving the two equations, the required point of intersection, ‘ P’ is got.
The required solution of P is (34, 3)
So, maximum chairs will be 34and tables will be 3
Now, maximum profit = (34 × $35) + (3 × $25)
= 1190 + 75
= $1265
Chapter 3 Solutions
Glencoe Algebra 2 Student Edition C2014
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