
To express each library’s number of books as matrix, then find out total number of books of each type and also more books in Library A than in C.

Answer to Problem 21PPS
(a)
(b) Total number of, Novels = 29000
Biographies = 15700
Children’s books = 8300
(c) Library A has more books than C, by,
Novels = 6000
Biographies = 4300
Children’s books = 4200
Explanation of Solution
Given Information
Library A, Novels = 10000 Biographies = 5000 Children’s books = 5000 Library B, Novels = 15000 Biographies = 10000 Children’s books = 2500 Library C, Novels = 4000 Biographies = 700 Children’s books = 800
Calculation
(a)
We write matrix A, B and C as per the respective names of the library.
So,
(b)
For finding out the total number of books of each type, we will have to add all the three matrices,
So, A + B + C =
⇒ A + B + C =
Hence, Total of, Novels = 29000
Biographies = 15700
Children’s books = 8300
(c)
For the calculation of, more books in library A than in C, we will have to subtract both the matrices,
So,
A − C =
=
Therefore, Library A has more books than C, by,
Novels = 6000
Biographies = 4300
Children’s books = 4200
(d)
A + B =
=
The matrix, A + B, shows the total number of books of each kind in both the libraries, as
In library A and B, we have total,
Novels = 25000
Biographies = 15000
Children’s books = 7500
Chapter 3 Solutions
Glencoe Algebra 2 Student Edition C2014
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