Glencoe Algebra 2 Student Edition C2014
Glencoe Algebra 2 Student Edition C2014
1st Edition
ISBN: 9780076639908
Author: McGraw-Hill Glencoe
Publisher: MCG
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Concept explainers

Unitary Method
The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.
Speed, Time, and Distance
Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 …
Profit and Loss
The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.
Units and Measurements
Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experime…
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Question
Book Icon
Chapter 3.8, Problem 43STP
To determine

To choose : the correct number of medium cones sold by the Yogurt Shoppe.

     A 11         B. 17         C. 24         D. 36

Expert Solution & Answer
Check Mark

Answer to Problem 43STP

C. 24

Explanation of Solution

Given information: The yogurt Shoppe sells cones in three sizes: small, $0.89; medium, $1.19; and large,$1.39. One day Santos sold 52 cones. He sold seven more medium cones than small cones. He sold $58.98 in cones.

Calculation:

Let the Yogurt Shoppe sold x small cones and y large cones. Since he sold seven more medium cones than small cones, therefore, the number of mediunm cones sold by him was x+7.

Total number of cones sold by him is 52.

Therefore,

  x+(x+7)+y=522x+y=45    ......(1)

He sold $58.98 in cones.

Therefore,

  0.89x+1.19(x+7)+1.39y=58.980.89x+1.19x+8.33+1.39y=58.982.08x+1.39y=50.65    ......(2)

From equation (1), we have

  y=45−2x

From equation (2)

  2.08x+1.39(45−2x)=50.652.08x+62.55−2.78x=50.65−0.7x=−11.9x=17

Thus, number of medium cones sold = x+ 7= 17+7 =24

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Chapter 3.8, Problem 42HP
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Chapter 3.8, Problem 44STP

Chapter 3 Solutions

Glencoe Algebra 2 Student Edition C2014

Ch. 3.1 - Prob. 1ECh. 3.1 - Prob. 2ECh. 3.1 - Prob. 3ECh. 3.1 - Prob. 4ECh. 3.1 - Prob. 5ECh. 3.1 - Prob. 6ECh. 3.1 - Prob. 7ECh. 3.1 - Prob. 8ECh. 3.1 - Prob. 9ECh. 3.1 - Prob. 10E
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Prob. 72SRCh. 3.7 - Prob. 73SCh. 3.7 - Prob. 74SCh. 3.7 - Prob. 75SCh. 3.8 - Prob. 1GPCh. 3.8 - Prob. 2AGPCh. 3.8 - Prob. 2BGPCh. 3.8 - Prob. 3GPCh. 3.8 - Prob. 1CYUCh. 3.8 - Prob. 2CYUCh. 3.8 - Prob. 3CYUCh. 3.8 - Prob. 4CYUCh. 3.8 - Prob. 5CYUCh. 3.8 - Prob. 6CYUCh. 3.8 - Prob. 7CYUCh. 3.8 - Prob. 8CYUCh. 3.8 - Prob. 9CYUCh. 3.8 - Prob. 10CYUCh. 3.8 - Prob. 11CYUCh. 3.8 - Prob. 12CYUCh. 3.8 - Prob. 13PPSCh. 3.8 - Prob. 14PPSCh. 3.8 - Prob. 15PPSCh. 3.8 - Prob. 16PPSCh. 3.8 - Prob. 17PPSCh. 3.8 - Prob. 18PPSCh. 3.8 - Prob. 19PPSCh. 3.8 - Prob. 20PPSCh. 3.8 - Prob. 21PPSCh. 3.8 - Prob. 22PPSCh. 3.8 - Prob. 23PPSCh. 3.8 - Prob. 24PPSCh. 3.8 - Prob. 25PPSCh. 3.8 - Prob. 26PPSCh. 3.8 - Prob. 27PPSCh. 3.8 - Prob. 28PPSCh. 3.8 - Prob. 29PPSCh. 3.8 - Prob. 30PPSCh. 3.8 - Prob. 31PPSCh. 3.8 - Prob. 32PPSCh. 3.8 - Prob. 33PPSCh. 3.8 - Prob. 34PPSCh. 3.8 - Prob. 35PPSCh. 3.8 - Prob. 36PPSCh. 3.8 - Prob. 37PPSCh. 3.8 - Prob. 38HPCh. 3.8 - Prob. 39HPCh. 3.8 - Prob. 40HPCh. 3.8 - Prob. 41HPCh. 3.8 - Prob. 42HPCh. 3.8 - Prob. 43STPCh. 3.8 - Prob. 44STPCh. 3.8 - Prob. 45STPCh. 3.8 - Prob. 46STPCh. 3.8 - Prob. 47SRCh. 3.8 - Prob. 48SRCh. 3.8 - Prob. 49SRCh. 3.8 - Prob. 50SRCh. 3.8 - Prob. 51SRCh. 3.8 - Prob. 52SRCh. 3.8 - Prob. 53SRCh. 3.8 - Prob. 54SCh. 3.8 - Prob. 55SCh. 3.8 - Prob. 56SCh. 3.8 - Prob. 1ECh. 3.8 - Prob. 2ECh. 3.8 - Prob. 3ECh. 3.8 - Prob. 4ECh. 3.8 - Prob. 5ECh. 3.8 - Prob. 6ECh. 3 - Prob. 1QCCh. 3 - Prob. 2QCCh. 3 - Prob. 3QCCh. 3 - Prob. 4QCCh. 3 - Prob. 5QCCh. 3 - Prob. 6QCCh. 3 - Prob. 7QCCh. 3 - Prob. 8QCCh. 3 - Prob. 9QCCh. 3 - Prob. 10QCCh. 3 - Prob. 11QCCh. 3 - Prob. 12QCCh. 3 - Prob. 13QCCh. 3 - Prob. 14QCCh. 3 - Prob. 1SGRCh. 3 - Prob. 2SGRCh. 3 - Prob. 3SGRCh. 3 - Prob. 4SGRCh. 3 - Prob. 5SGRCh. 3 - Prob. 6SGRCh. 3 - Prob. 7SGRCh. 3 - Prob. 8SGRCh. 3 - Prob. 9SGRCh. 3 - Prob. 10SGRCh. 3 - Prob. 11SGRCh. 3 - Prob. 12SGRCh. 3 - Prob. 13SGRCh. 3 - Prob. 14SGRCh. 3 - Prob. 15SGRCh. 3 - Prob. 16SGRCh. 3 - Prob. 17SGRCh. 3 - Prob. 18SGRCh. 3 - Prob. 19SGRCh. 3 - Prob. 20SGRCh. 3 - Prob. 21SGRCh. 3 - Prob. 22SGRCh. 3 - Prob. 23SGRCh. 3 - Prob. 24SGRCh. 3 - Prob. 25SGRCh. 3 - Prob. 26SGRCh. 3 - Prob. 27SGRCh. 3 - Prob. 28SGRCh. 3 - Prob. 29SGRCh. 3 - Prob. 30SGRCh. 3 - Prob. 31SGRCh. 3 - Prob. 32SGRCh. 3 - Prob. 33SGRCh. 3 - Prob. 34SGRCh. 3 - Prob. 35SGRCh. 3 - Prob. 36SGRCh. 3 - Prob. 37SGRCh. 3 - Prob. 38SGRCh. 3 - Prob. 39SGRCh. 3 - Prob. 40SGRCh. 3 - Prob. 41SGRCh. 3 - Prob. 42SGRCh. 3 - Prob. 43SGRCh. 3 - Prob. 44SGRCh. 3 - Prob. 45SGRCh. 3 - Prob. 46SGRCh. 3 - Prob. 47SGRCh. 3 - Prob. 48SGRCh. 3 - Prob. 1PTCh. 3 - Prob. 2PTCh. 3 - Prob. 3PTCh. 3 - Prob. 4PTCh. 3 - Prob. 5PTCh. 3 - Prob. 6PTCh. 3 - Prob. 7PTCh. 3 - Prob. 8PTCh. 3 - Prob. 9PTCh. 3 - Prob. 10PTCh. 3 - Prob. 11PTCh. 3 - Prob. 12PTCh. 3 - Prob. 13PTCh. 3 - Prob. 14PTCh. 3 - Prob. 15PTCh. 3 - Prob. 16PTCh. 3 - Prob. 17PTCh. 3 - Prob. 18PTCh. 3 - Prob. 19PTCh. 3 - Prob. 20PTCh. 3 - Prob. 21PTCh. 3 - Prob. 22PTCh. 3 - Prob. 1ECh. 3 - Prob. 2ECh. 3 - Prob. 3ECh. 3 - Prob. 4ECh. 3 - Prob. 5ECh. 3 - Prob. 6ECh. 3 - Prob. 7ECh. 3 - Prob. 8ECh. 3 - Prob. 1STPCh. 3 - Prob. 2STPCh. 3 - Prob. 3STPCh. 3 - Prob. 4STPCh. 3 - Prob. 5STPCh. 3 - Prob. 6STPCh. 3 - Prob. 7STPCh. 3 - Prob. 8STPCh. 3 - Prob. 9STPCh. 3 - Prob. 10STPCh. 3 - Prob. 11STPCh. 3 - Prob. 12STPCh. 3 - Prob. 13STP

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