Explanation Given information: The width of the bar ( b ) is 15 mm. The depth of the bar ( a ) is 30 mm. The modulus of rigidity ( G ) is 26 MPa. The length of the bar ( L ) is 750 mm. The angle of twist ( ϕ ) is 0.6 ° . Calculation: Convert the unit of angle of twist from degree to radians: ϕ = ϕ deg × π 180 ° Here, ϕ deg is the angle of twist in degree. Substitute 0.6 ° for ϕ deg . ϕ = 0.6 ° × π 180 ° = 10.472 × 10 − 3 radians Calculate the depth to width ratio of a b . Here, a is the depth of the bar and b is the width of the bar. Substitute 30 mm for a , 15 mm for b . a b = 30 15 = 2 mm Refer Table 3.1, “Coefficient for rectangular bars in torsion” from the textbook. The value of coefficients c 1 is 0.246 and c 2 is 0.229

7th Edition

ISBN: 9780073398235

Author: Ferdinand P. Beer, E. Russell Johnston Jr., John T. DeWolf, David F. Mazurek

Publisher: McGraw-Hill Education

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Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial…

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Chapter 3.10, Problem 127P

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Find the maximum shearing stress (τmax) in the bar.

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Chapter 3.10, Problem 126P

Chapter 3.10, Problem 128P

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Mechanics of Materials, 7th Edition

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Find the maximum shearing stress ( τ max ) in the bar.

Solution Summary: The author explains how to convert the unit of angle of twist from degree to radians.

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