Chapter 3, Problem 88A

To determine

The distance travelled by the bicycle.

Answer to Problem 88A

  $s=8\text{ m}$

Explanation of Solution

Given info:

Initial speed of bicycle, $u=0.0\text{ m/s}$

Final speed of bicycle, $v=4.0\text{ m/s}$

Time taken, $t=4.0\text{ s}$

Formula used:

Kinematics equations:

  $v=u+at$

  $s=ut+\frac{1}{2}a{t}^2$

Where,

  $u=$ Initial speed.

  $v=$ Final speed.

  $s=$ Distance travelled.

  $a=$ Acceleration.

Calculation:

Let, acceleration of bicycle in time $t$ be $a$ and distance travelled by the bicycle be $s$ .

From first equation of kinematics:

  $\begin{array}{c}a=\frac{v-u}{t}\\ =\frac{4-0}{4}\\ =1{\text{ m/s}}^2\end{array}$

From second equation of kinematics:

  $\begin{array}{c}s=ut+\frac{1}{2}a{t}^2\\ =0\times 4+\frac{1}{2}\times 1\times {\left(4.0\right)}^2\\ =8\text{ m}\end{array}$

Conclusion:

Distance travelled by the bicycle: $\text{8 m}$