Glencoe Physics: Principles and Problems, Student Edition
Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN: 9780078807213
Author: Paul W. Zitzewitz
Publisher: Glencoe/McGraw-Hill
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Chapter 3, Problem 59A

a.

To determine

Acceleration of the object.

a.

Expert Solution
Check Mark

Answer to Problem 59A

Acceleration of object for first 5 min is 6 m/min2 .

Explanation of Solution

Given:

Velocity time graph is given

  Glencoe Physics: Principles and Problems, Student Edition, Chapter 3, Problem 59A , additional homework tip  1

Time is from 0 to 5 min. So, t = 5 min

Formula Used:

Acceleration of an object is equal to change if velocity is with respect to time.

Mathematically acceleration is

  a=vut

Here, v is final velocity, u is initial velocity and t is the time taken to reach final velocity from initial velocity.

Calculation:

For the first 5 min, velocity changes from 0 m/min to 30 m/min.

Therefore, initial velocity u = 0 m/min

And final velocity v = 30 m/min.

So, on substituting the values

  a=3005=6 m/min2

Conclusion:

Therefore, the acceleration of the object is a=6 m/min2 .

b.

To determine

Acceleration of the object.

b.

Expert Solution
Check Mark

Answer to Problem 59A

Acceleration of object for between 5 to 10 min is 0 m/min2 .

.

Explanation of Solution

Given:

Velocity time graph is given

  Glencoe Physics: Principles and Problems, Student Edition, Chapter 3, Problem 59A , additional homework tip  2

Time is from 5 to 10 min. So, t = 5 min

Formula Used:

Acceleration of an object is equal to change if velocity is with respect to time.

Mathematically acceleration is

  a=vut

Here, v is final velocity, u is initial velocity and t is the time taken to reach final velocity from initial velocity.

Calculation:

Between 5 to 10 min, there is no change in velocity.

Therefore, initial velocity u = 30 m/min, and final velocity v = 30 m/min.

So, on substituting the values,

  a=30305=0 m/min2

Conclusion:

Therefore, the acceleration of the object is a=0 m/min2 .

c.

To determine

Acceleration of the object.

c.

Expert Solution
Check Mark

Answer to Problem 59A

Acceleration of object for between 10 to 15 min is 2 m/min2 .

Explanation of Solution

Given:

Velocity time graph is given

  Glencoe Physics: Principles and Problems, Student Edition, Chapter 3, Problem 59A , additional homework tip  3

Time is from 10 to 15 min. So, t = 5 min.

Formula Used:

Acceleration of an object is equal to change if velocity with respect to time.

Mathematically acceleration is

  a=vut

Here, v is final velocity, u is initial velocity and t is the time taken to reach final velocity from initial velocity.

Calculation:

Between 10 to 15 min velocity changes from 30 m/min to 20 m/min.

Therefore, initial velocity u = 30 m/min.

And final velocity v = 20 m/min.

So, on substituting the values

  a=20305=2 m/min2

Conclusion:

Therefore, the acceleration of the object is a=2 m/min2 .

d.

To determine

Acceleration of the object.

d.

Expert Solution
Check Mark

Answer to Problem 59A

Acceleration of object for between 20 to 25 min is 4 m/min2 .

Explanation of Solution

Given:

Velocity time graph is given;

  Glencoe Physics: Principles and Problems, Student Edition, Chapter 3, Problem 59A , additional homework tip  4

Time is from 20 to 25 min. So, t = 5 min

Formula Used:

Acceleration of an object is equal to change if velocity with respect to time.

Mathematically acceleration is

  a=vut

Here, v is final velocity, u is initial velocity and t is the time taken to reach final velocity from initial velocity.

Calculation:

Between 20 to 25 min, the velocity changes from 20 m/min to 0 m/min.

Therefore, initial velocity u = 20 m/min.

And final velocity v = 0 m/min.

So, on substituting the values

  a=0205=4 m/min2

Conclusion:

Therefore, the acceleration of the object is a=4 m/min2 .

Chapter 3 Solutions

Glencoe Physics: Principles and Problems, Student Edition

Ch. 3.1 - Prob. 11SSCCh. 3.1 - Prob. 12SSCCh. 3.1 - Prob. 13SSCCh. 3.1 - Prob. 14SSCCh. 3.1 - Prob. 15SSCCh. 3.2 - Prob. 16PPCh. 3.2 - Prob. 17PPCh. 3.2 - Prob. 18PPCh. 3.2 - Prob. 19PPCh. 3.2 - Prob. 20PPCh. 3.2 - Prob. 21PPCh. 3.2 - Prob. 22PPCh. 3.2 - Prob. 23PPCh. 3.2 - Prob. 24PPCh. 3.2 - Prob. 25PPCh. 3.2 - Prob. 26PPCh. 3.2 - Prob. 27PPCh. 3.2 - Prob. 28PPCh. 3.2 - Prob. 29PPCh. 3.2 - Prob. 30PPCh. 3.2 - Prob. 31PPCh. 3.2 - Prob. 32PPCh. 3.2 - Prob. 33SSCCh. 3.2 - Prob. 34SSCCh. 3.2 - Prob. 35SSCCh. 3.2 - Prob. 36SSCCh. 3.2 - Prob. 37SSCCh. 3.2 - Prob. 38SSCCh. 3.2 - Prob. 39SSCCh. 3.2 - Prob. 40SSCCh. 3.3 - Prob. 41PPCh. 3.3 - Prob. 42PPCh. 3.3 - Prob. 43PPCh. 3.3 - Prob. 44PPCh. 3.3 - Prob. 45PPCh. 3.3 - Prob. 46PPCh. 3.3 - Prob. 47SSCCh. 3.3 - Prob. 48SSCCh. 3.3 - Prob. 49SSCCh. 3.3 - Prob. 50SSCCh. 3.3 - Prob. 51SSCCh. 3.3 - Prob. 52SSCCh. 3 - Prob. 53ACh. 3 - Prob. 54ACh. 3 - Prob. 55ACh. 3 - Prob. 56ACh. 3 - Prob. 57ACh. 3 - Prob. 58ACh. 3 - Prob. 59ACh. 3 - Prob. 60ACh. 3 - Prob. 61ACh. 3 - Prob. 62ACh. 3 - Prob. 63ACh. 3 - Prob. 64ACh. 3 - Prob. 65ACh. 3 - Prob. 66ACh. 3 - Prob. 67ACh. 3 - Prob. 68ACh. 3 - Prob. 69ACh. 3 - Prob. 70ACh. 3 - Prob. 71ACh. 3 - Prob. 72ACh. 3 - Prob. 73ACh. 3 - Prob. 74ACh. 3 - Prob. 75ACh. 3 - Prob. 76ACh. 3 - Prob. 77ACh. 3 - Prob. 78ACh. 3 - Prob. 79ACh. 3 - Prob. 80ACh. 3 - Prob. 81ACh. 3 - Prob. 82ACh. 3 - Prob. 83ACh. 3 - Prob. 84ACh. 3 - Prob. 85ACh. 3 - Prob. 86ACh. 3 - Prob. 87ACh. 3 - Prob. 88ACh. 3 - Prob. 89ACh. 3 - Prob. 90ACh. 3 - Prob. 91ACh. 3 - Prob. 92ACh. 3 - Prob. 93ACh. 3 - Prob. 94ACh. 3 - Prob. 95ACh. 3 - Prob. 96ACh. 3 - Prob. 97ACh. 3 - Prob. 98ACh. 3 - Prob. 100ACh. 3 - Prob. 101ACh. 3 - Prob. 102ACh. 3 - Prob. 103ACh. 3 - Prob. 104ACh. 3 - Prob. 105ACh. 3 - Prob. 1STPCh. 3 - Prob. 2STPCh. 3 - Prob. 3STPCh. 3 - Prob. 4STPCh. 3 - Prob. 5STPCh. 3 - Prob. 6STPCh. 3 - Prob. 7STPCh. 3 - Prob. 8STPCh. 3 - Prob. 9STPCh. 3 - Prob. 10STP
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