Chapter 3, Problem 90A

(a)

To determine

The position-time graph of the motion of the ball.

Explanation of Solution

Given:

The position versus time data for the motion of a steel ball is given.

Calculation:

Refer to the position versus time data table for the motion of steel ball.

Take five divisions for each $10\text{m}$ of the travel on the $x$ axis (horizontal axis).

Take five divisions for each $1\text{s}$ of the time on the $t$ axis (vertical axis).

Plot the points of the position versus time data table in the graph as shown below.

  

(b)

To determine

The distance rolled by the ball at the end of $2.2\text{s}$ .

Answer to Problem 90A

The distance rolled by the ball at the end of $2.2\text{s}$ is $10\text{m}$ .

Explanation of Solution

Given:

The position versus time data for the motion of a steel ball is given.

Formula used:

Calculation:

Refer to position versus time graph of Part (a).

The distance corresponding to time $2.2\text{s}$ is $10\text{m}$ .

Hence, the distance rolled by the ball after of $2.2\text{s}$ is $10\text{m}$ .

Conclusion:

Thus, the distance rolled by the ball after $2.2\text{s}$ is $10\text{m}$ .