Chapter 3, Problem 1STP

To determine

To Choose: The correct option.

Answer to Problem 1STP

Option C: $16\text{m}$

Explanation of Solution

Given:

Acceleration of ball, $a=2.0{\text{m/s}}^{\text{2}}$

Initial velocity of the ball, $u=0$

Time elapsed, $t=4.0\text{s}$

Formula Used:

Second equation of motion:

  $s=ut+\frac{1}{2}a{t}^2$

Where, s is the displacement, u is the initial velocity, t is the time and a is the acceleration.

Calculations:

Substitute the values and solve:

  $\begin{array}{l}s=ut+\frac{1}{2}a{t}^2\\ s=0+\frac{1}{2}\left(2\right){\left(4\right)}^2\\ s=16\text{m}\end{array}$

Conclusion:

Thus, correct option is C.