Chapter 3.2, Problem 23PP

To determine

The time for her to stop.

Answer to Problem 23PP

The time taken to stop is $t=8.75\text{ s}$ .

Explanation of Solution

Given:

Initial velocity, $u=1.75\text{ m/s}$

Final velocity, $v=\text{ 0 m/s}$

Acceleration, $a=\text{-0}{\text{.20 m/s}}^{-2}$

Formula Used:

Average acceleration is $a=\frac{v-u}{t}$

v is the final velocity

u is the initial velocity

t is the time.

Calculation:

  $a=\frac{v-u}{t}$

  $\text{-0}{\text{.20 m/s}}^{-2}=\frac{0-1.75\text{ m/s}}{t}$

  $t=8.75\text{ s}$

Conclusion:

The time taken to stop is $t=8.75\text{ s}$ .