World of Chemistry
7th Edition
ISBN: 9780618562763
Author: Steven S. Zumdahl
Publisher: Houghton Mifflin College Div
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Chapter 3, Problem 55A
Interpretation Introduction
Interpretation :
Whether it is possible for the same two elements to form more than one compound or not needs to be explained. Whether it is consistent with Dalton’s atomic theory needs to be explained with example.
Concept Introduction :
When the different elements are combined in a fixed ratio they form a compound. The elements with multiple proportions form more than one compound, this is in accordance with the Dalton's atomic theory.
Expert Solution & Answer
Answer to Problem 55A
Yes, the same two elements can form more than one compound. This is explained by the third law of multiple proportions of Dalton’s atomic theory.
Explanation of Solution
The law of multiple proportions states that when the similar two elements form more than one compound, the combination of elements with the same mass of the other element is in the ratio of small whole numbers.
Example −
The hydrogen and oxygen reacted to form more than one compound like water, and hydrogen peroxide.
Conclusion
The different combinations of similar elements can react to form more than one compound, and new compounds are formed with a new different ratio.
Chapter 3 Solutions
World of Chemistry
Ch. 3.1 - Prob. 1RQCh. 3.1 - Prob. 2RQCh. 3.1 - Prob. 3RQCh. 3.1 - Prob. 4RQCh. 3.1 - Prob. 5RQCh. 3.1 - Prob. 6RQCh. 3.2 - Prob. 1RQCh. 3.2 - Prob. 2RQCh. 3.2 - Prob. 3RQCh. 3.2 - Prob. 4RQ
Ch. 3.2 - Prob. 5RQCh. 3.2 - Prob. 6RQCh. 3.3 - Prob. 1RQCh. 3.3 - Prob. 2RQCh. 3.3 - Prob. 3RQCh. 3.3 - Prob. 4RQCh. 3.3 - Prob. 5RQCh. 3.3 - Prob. 6RQCh. 3.3 - Prob. 7RQCh. 3.4 - Prob. 1RQCh. 3.4 - Prob. 2RQCh. 3.4 - Prob. 3RQCh. 3.4 - Prob. 4RQCh. 3.4 - Prob. 5RQCh. 3.4 - Prob. 6RQCh. 3.4 - Prob. 7RQCh. 3.4 - Prob. 8RQCh. 3.5 - Prob. 1RQCh. 3.5 - Prob. 2RQCh. 3.5 - Prob. 3RQCh. 3.5 - Prob. 4RQCh. 3.5 - Prob. 5RQCh. 3 - Prob. 1ACh. 3 - Prob. 2ACh. 3 - Prob. 3ACh. 3 - Prob. 4ACh. 3 - Prob. 5ACh. 3 - Prob. 6ACh. 3 - Prob. 7ACh. 3 - Prob. 8ACh. 3 - Prob. 9ACh. 3 - Prob. 10ACh. 3 - Prob. 11ACh. 3 - Prob. 12ACh. 3 - Prob. 13ACh. 3 - Prob. 14ACh. 3 - Prob. 15ACh. 3 - Prob. 16ACh. 3 - Prob. 17ACh. 3 - Prob. 18ACh. 3 - Prob. 19ACh. 3 - Prob. 20ACh. 3 - Prob. 21ACh. 3 - Prob. 22ACh. 3 - Prob. 23ACh. 3 - Prob. 24ACh. 3 - Prob. 25ACh. 3 - Prob. 26ACh. 3 - Prob. 27ACh. 3 - Prob. 28ACh. 3 - Prob. 29ACh. 3 - Prob. 30ACh. 3 - Prob. 31ACh. 3 - Prob. 32ACh. 3 - Prob. 33ACh. 3 - Prob. 34ACh. 3 - Prob. 35ACh. 3 - Prob. 36ACh. 3 - Prob. 37ACh. 3 - Prob. 38ACh. 3 - Prob. 39ACh. 3 - Prob. 40ACh. 3 - Prob. 41ACh. 3 - Prob. 42ACh. 3 - Prob. 43ACh. 3 - Prob. 44ACh. 3 - Prob. 45ACh. 3 - Prob. 46ACh. 3 - Prob. 47ACh. 3 - Prob. 48ACh. 3 - Prob. 49ACh. 3 - Prob. 50ACh. 3 - Prob. 51ACh. 3 - Prob. 52ACh. 3 - Prob. 53ACh. 3 - Prob. 54ACh. 3 - Prob. 55ACh. 3 - Prob. 56ACh. 3 - Prob. 57ACh. 3 - Prob. 58ACh. 3 - Prob. 59ACh. 3 - Prob. 60ACh. 3 - Prob. 1STPCh. 3 - Prob. 2STPCh. 3 - Prob. 3STPCh. 3 - Prob. 4STPCh. 3 - Prob. 5STPCh. 3 - Prob. 6STPCh. 3 - Prob. 7STPCh. 3 - Prob. 8STPCh. 3 - Prob. 9STPCh. 3 - Prob. 10STP
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