
Concept explainers
Interpretation:
The particle in an atom which is most responsible for the chemical properties of the atom needs to be determined. The location of these particles in the atom needs to be determined.
Concept introduction:
The smallest unit of element is termed as atom, it cannot be further divided. The neutron and protons present together in the nucleus and electrons are found in the outer shell of the atom. The number of electron is same as the number of protons. The subatomic particles are charged except neutrons.

Answer to Problem 22A
The electrons are located at outer side of the nucleus of an atom, it is responsible for the chemical properties of the atom.
Explanation of Solution
An atom has protons, neutron and electron as the subatomic particle. The number of protons present in the nucleus is representing the
The number of protons, neutrons and electrons present in an atom, give the information to calculate atomic number and mass number, and other specific properties are explained by the number of protons and electrons.
Chapter 3 Solutions
World of Chemistry
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- Take a look at this molecule, and then answer the questions in the table below it. CH2OH H H H OH OH OH CH2OH H H H H OH H H OH H OH Is this a reducing sugar? yes α β ロ→ロ no ☑ yes Does this molecule contain a glycosidic bond? If you said this molecule does contain a glycosidic bond, write the symbol describing it. O no 0+0 If you said this molecule does contain a glycosidic bond, write the common names (including anomer and enantiomer labels) of the molecules that would be released if that bond were hydrolyzed. If there's more than one molecule, separate each name with a comma. ☐arrow_forwardAnswer the questions in the table below about this molecule: H₂N-CH₂ -C—NH–CH–C—NH–CH—COO- CH3 CH CH3 What kind of molecule is this? 0= CH2 C If you said the molecule is a peptide, write a description of it using 3-letter codes separated ☐ by dashes. polysaccharide peptide amino acid phospolipid none of the above Хarrow_forwardDraw a Haworth projection of a common cyclic form of this monosaccharide: CH₂OH C=O HO H H -OH H OH CH₂OH Click and drag to start drawing a structure. : ☐ Х S '☐arrow_forward
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