Chapter 3, Problem 3.69P

(a)

Interpretation Introduction

Interpretation:Volume in $2.26\text{ M KOH}$ that has $8.42\text{ g}$ solute should be calculated.

Concept introduction:The formula to evaluate moles from molarity is given as follows:

  $n=MV$

Where,

• $V$represents volume.
• $M$represents molarity.
• $n$represents number of moles.

The formula to convert mass in gram to moles is as follows:

  $\text{Mass}=\left(\text{Number of moles}\right)\left(\text{Molar mass}\right)$

(b)

Interpretation Introduction

Interpretation:Number of ${\text{Cu}}^{2+}$ in $500\text{ mL}$ of $\text{52 L}$ of $\text{2}\text{.3 M copper}\left(\text{II}\right)$ chloride solution is to be calculated.

Concept introduction:The formula to evaluate moles from molarity is given as follows:

  $n=MV$

Where,

• $V$represents volume.
• $M$represents molarity.
• $n$represents number of moles.

The formula to convert mass in gram to moles is as follows:

  $\text{Mass}=\left(\text{Number of moles}\right)\left(\text{Molar mass}\right)$

(c)

Interpretation Introduction

Interpretation:Molarity in $\text{275 mL}$ of $\text{135 mmol}$ glucose solution is to be calculated.

Concept introduction:The formula to evaluate moles from molarity is given as follows:

  $n=MV$

Where,

• $V$represents volume.
• $M$represents molarity.
• $n$represents number of moles.

The formula to convert mass in gram to moles is as follows:

  $\text{Mass}=\left(\text{Number of moles}\right)\left(\text{Molar mass}\right)$