Chapter 3, Problem 3.11P

(a)

Interpretation Introduction

Interpretation:Mass in grams for $0.68{\text{ mol KMnO}}_4$ is to be calculated.

Concept introduction: The formula to convert moles to mass in grams is as follows:

  $\text{Mass}=\left(\text{Number of moles}\right)\left(\text{molar mass}\right)$

The formula to convert number of atoms to moles is as follows:

  $\text{Number of moles}=\frac{\text{Given number of molecules}}{6.022\times {10}^{23}}$

(b)

Interpretation Introduction

Interpretation: Moles of $\text{O}$ atoms in $\text{8}\text{.18 g Ba}{\left({\text{NO}}_3\right)}_2$ is to be calculated.

Concept introduction:The formula to convert mass in grams to moles is as follows:

  $\text{Number of moles}=\frac{\text{Given mass}}{\text{molar mass}}$

(c)

Interpretation Introduction

Interpretation:Number of $\text{O}$ atoms in $\text{7}\text{.3}\times {\text{10}}^{-3}{\text{ g CaSO}}_4\cdot 2{\text{H}}_{\text{2}}\text{O}$ is to be calculated.

Concept introduction:The formula to convert number of atoms to moles is as follows:

  $\text{Number of molecules}=\left(\text{Number of moles}\right)\left(6.022\times {10}^{23}\right)$

The formula to convert mass in grams to moles is as follows:

  $\text{Number of moles}=\frac{\text{Given mass}}{\text{molar mass}}$