Empirical formula of the compound that has 0.063 mol Cl and 0 .22 mol O should be determined. Concept introduction: An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule. The steps to determine empirical formula are stated as follows: Divide mass of element by its molar mass to convert mass to moles as follows: Amount ( mol ) = ( Given mass ( g ) ) ( 1 mol No . of grams ) Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula. In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

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Answer 1

Question

Chapter 3, Problem 3.29P

(a)

Interpretation Introduction

Interpretation: Empirical formula of the compound that has 0.063 mol Cl and 0.22 mol O should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

(b)

Interpretation Introduction

Interpretation: Empirical formula of a compound that has 2.45 g Si and 12.4 g Cl should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

(c)

Interpretation Introduction

Interpretation: Empirical formula of the compound that has 27.3 % C and 72.7 % O should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

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Answer 2

Question

Chapter 3, Problem 3.29P

(a)

Interpretation Introduction

Interpretation: Empirical formula of the compound that has 0.063 mol Cl and 0.22 mol O should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

(b)

Interpretation Introduction

Interpretation: Empirical formula of a compound that has 2.45 g Si and 12.4 g Cl should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

(c)

Interpretation Introduction

Interpretation: Empirical formula of the compound that has 27.3 % C and 72.7 % O should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

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Answer 3

Question

Chapter 3, Problem 3.29P

(a)

Interpretation Introduction

Interpretation: Empirical formula of the compound that has 0.063 mol Cl and 0.22 mol O should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

(b)

Interpretation Introduction

Interpretation: Empirical formula of a compound that has 2.45 g Si and 12.4 g Cl should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

(c)

Interpretation Introduction

Interpretation: Empirical formula of the compound that has 27.3 % C and 72.7 % O should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

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Answer 4

Question

Chapter 3, Problem 3.29P

(a)

Interpretation Introduction

Interpretation: Empirical formula of the compound that has 0.063 mol Cl and 0.22 mol O should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

(b)

Interpretation Introduction

Interpretation: Empirical formula of a compound that has 2.45 g Si and 12.4 g Cl should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

(c)

Interpretation Introduction

Interpretation: Empirical formula of the compound that has 27.3 % C and 72.7 % O should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

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Answer 5

Chapter 3, Problem 3.29P

(a)

Interpretation Introduction

Interpretation: Empirical formula of the compound that has 0.063 mol Cl and 0.22 mol O should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

(b)

Interpretation Introduction

Interpretation: Empirical formula of a compound that has 2.45 g Si and 12.4 g Cl should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

(c)

Interpretation Introduction

Interpretation: Empirical formula of the compound that has 27.3 % C and 72.7 % O should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

Answer 6

Chapter 3, Problem 3.29P

(a)

Interpretation Introduction

Interpretation: Empirical formula of the compound that has 0.063 mol Cl and 0.22 mol O should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

Answer 7

Chapter 3, Problem 3.29P

(a)

Interpretation Introduction

Interpretation: Empirical formula of the compound that has 0.063 mol Cl and 0.22 mol O should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

Answer 8

(b)

Interpretation Introduction

Interpretation: Empirical formula of a compound that has 2.45 g Si and 12.4 g Cl should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

Answer 9

(b)

Interpretation Introduction

Interpretation: Empirical formula of a compound that has 2.45 g Si and 12.4 g Cl should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

Answer 10

(c)

Interpretation Introduction

Interpretation: Empirical formula of the compound that has 27.3 % C and 72.7 % O should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

Answer 11

(c)

Interpretation Introduction

Interpretation: Empirical formula of the compound that has 27.3 % C and 72.7 % O should be determined.

Concept introduction:An empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule. The molecular formula depicts exact number of each atom found in a molecule.

The steps to determine empirical formula are stated as follows:

Divide mass of element by its molar mass to convert mass to moles as follows:

Amount(mol)=(Given mass(g))(1 molNo. of grams)

Number of moles thus calculated is written as subscript of element’s symbol and this results in a preliminary empirical formula.

In order to convert the moles to the whole number subscripts, each subscript is divided by the smallest subscript. Finally, empirical formula can be simply written from the molar ratio of each element specified at the superscript of each symbol present in the compound.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 3 - The atomic mass of Cl is 35.45 amu, and the atomic...Ch. 3 - (a) How many moles of C atoms are in 1 mol of...Ch. 3 - Prob. 3.3P Ch. 3 - How is the molecular mass of a compound the same...Ch. 3 - What advantage is there to using a counting unit...Ch. 3 - Prob. 3.6P Ch. 3 - Prob. 3.7P Ch. 3 - Calculate the molar mass of each of the following:...Ch. 3 - Prob. 3.9P Ch. 3 - Calculate the molar mass of each of the following:...

Solution Summary: The author explains how an empirical formula depicts the ratio of simplified whole-number of atoms contained in a molecule.

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