Chapter 3, Problem 3.61P

Interpretation Introduction

Interpretation: Mass of ${\text{Ca}}_3{\text{N}}_{\text{2}}$ formed when $\text{56}\text{.6 g Ca}$ reacts with $\text{30}{\text{.5 g N}}_2$ is to be calculated.

Concept introduction:The formula to convert mass in grams to moles is as follows:

  $\text{Number of moles}=\frac{\text{Given mass}}{\text{molar mass}}$

For some stoichiometric balanced equation; the reactant present in the smallest amount is consumed completely to form the product and thus governs the product formation.This reactant is known as limiting reactant.On the basis of the stoichiometric ratio by which substrates combine, moles of product formed from each reactant can be calculated.