Chapter 3, Problem 3.13P

(a)

Interpretation Introduction

Interpretation:Mass in grams present in $6.44\times {10}^{-2}{\text{ mol MnSO}}_4$ is to be calculated.

Concept introduction: The formula to convert moles to mass in grams is as follows:

  $\text{Mass}=\left(\text{Number of moles}\right)\left(\text{molar mass}\right)$

The formula to convert number of atoms to moles is as follows:

  $\text{Number of moles}=\frac{\text{Given number of molecules}}{6.022\times {10}^{23}}$

(b)

Interpretation Introduction

Interpretation: Moles of compound in $\text{15}\text{.8 kg Fe}{\left({\text{ClO}}_{\text{4}}\right)}_3$ is to be calculated.

Concept introduction: The formula to convert moles to mass in grams is as follows:

  $\text{Mass}=\left(\text{Number of moles}\right)\left(\text{molar mass}\right)$

The formula to convert number of atoms to moles is as follows:

  $\text{Number of moles}=\frac{\text{Given number of molecules}}{6.022\times {10}^{23}}$

(c)

Interpretation Introduction

Interpretation: Number of $\text{N}$ atoms in $\text{92}{\text{.6 mg NH}}_4{\text{NO}}_{\text{2}}$ is to be calculated.

Concept introduction: The formula to convert moles to mass in grams is as follows:

  $\text{Mass}=\left(\text{Number of moles}\right)\left(\text{molar mass}\right)$

The formula to convert number of atoms to moles is as follows:

  $\text{Number of moles}=\frac{\text{Given number of molecules}}{6.022\times {10}^{23}}$