FUND OF ENG THERMODYN(LLF)+WILEYPLUS
9th Edition
ISBN: 9781119391777
Author: MORAN
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 3, Problem 3.58P
To determine
Time taken for the temperature to reach
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
An object follows Newton's law of Heating/Cooling. If the object cools from 101°C to 81°C after 31minutes.
Note: the ambient temperature is 24°C.
How much more time(minutes) needs to pass to reach 44°C.
Show your solution in step by step process.
3) An ideal gas is enclosed in a cylinder with a movable piston on top of it. The
piston has a mass of 8 000 g and an area of 5.00 cm2 and is free to slide up and
down, keeping the pressure of the gas constant. How much work is done on the
gas as the temperature of 0.200 mol of the gas is raised from 20.0°C to 300°C?
A mass of gas at an initial pressure of 28 bar, and with an internal energy of 1500 kJ, is contained in a well-insulated cyclinder of volume 0.06m3. The gas is allowed to expand behind a piston until its internal energy is 1400 kJ; the law of expansion is pv2= constant. Calculate.
(i) the work done
(ii) the final volume
(iii) the final pressure
Chapter 3 Solutions
FUND OF ENG THERMODYN(LLF)+WILEYPLUS
Ch. 3 - Prob. 3.1ECh. 3 - Prob. 3.2ECh. 3 - Prob. 3.3ECh. 3 - Prob. 3.4ECh. 3 - Prob. 3.6ECh. 3 - Prob. 3.7ECh. 3 - Prob. 3.8ECh. 3 - Prob. 3.9ECh. 3 - Prob. 3.10ECh. 3 - Prob. 3.11E
Ch. 3 - Prob. 3.12ECh. 3 - Prob. 3.13ECh. 3 - Prob. 3.1CUCh. 3 - Prob. 3.2CUCh. 3 - Prob. 3.3CUCh. 3 - Prob. 3.4CUCh. 3 - Prob. 3.5CUCh. 3 - Prob. 3.6CUCh. 3 - Prob. 3.7CUCh. 3 - Prob. 3.8CUCh. 3 - Prob. 3.9CUCh. 3 - Prob. 3.10CUCh. 3 - Prob. 3.11CUCh. 3 - Prob. 3.12CUCh. 3 - Prob. 3.13CUCh. 3 - Prob. 3.14CUCh. 3 - Prob. 3.15CUCh. 3 - Prob. 3.16CUCh. 3 - Prob. 3.17CUCh. 3 - Prob. 3.18CUCh. 3 - Prob. 3.19CUCh. 3 - Prob. 3.20CUCh. 3 - Prob. 3.21CUCh. 3 - Prob. 3.22CUCh. 3 - Prob. 3.23CUCh. 3 - Prob. 3.24CUCh. 3 - Prob. 3.25CUCh. 3 - Prob. 3.26CUCh. 3 - Prob. 3.27CUCh. 3 - Prob. 3.28CUCh. 3 - Prob. 3.29CUCh. 3 - Prob. 3.30CUCh. 3 - Prob. 3.31CUCh. 3 - Prob. 3.32CUCh. 3 - Prob. 3.33CUCh. 3 - Prob. 3.34CUCh. 3 - Prob. 3.35CUCh. 3 - Prob. 3.36CUCh. 3 - Prob. 3.37CUCh. 3 - Prob. 3.38CUCh. 3 - Prob. 3.39CUCh. 3 - Prob. 3.40CUCh. 3 - Prob. 3.41CUCh. 3 - Prob. 3.42CUCh. 3 - Prob. 3.43CUCh. 3 - Prob. 3.44CUCh. 3 - Prob. 3.45CUCh. 3 - Prob. 3.46CUCh. 3 - Prob. 3.47CUCh. 3 - Prob. 3.48CUCh. 3 - Prob. 3.49CUCh. 3 - Prob. 3.50CUCh. 3 - Prob. 3.51CUCh. 3 - Prob. 3.52CUCh. 3 - Prob. 3.1PCh. 3 - Prob. 3.2PCh. 3 - Prob. 3.3PCh. 3 - Prob. 3.4PCh. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10PCh. 3 - Prob. 3.11PCh. 3 - Prob. 3.12PCh. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - Prob. 3.16PCh. 3 - Prob. 3.17PCh. 3 - Prob. 3.18PCh. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Prob. 3.23PCh. 3 - Prob. 3.24PCh. 3 - Prob. 3.25PCh. 3 - Prob. 3.26PCh. 3 - Prob. 3.27PCh. 3 - Prob. 3.28PCh. 3 - Prob. 3.29PCh. 3 - Prob. 3.30PCh. 3 - Prob. 3.31PCh. 3 - Prob. 3.32PCh. 3 - Prob. 3.33PCh. 3 - Prob. 3.34PCh. 3 - Prob. 3.35PCh. 3 - Prob. 3.36PCh. 3 - Prob. 3.37PCh. 3 - Prob. 3.38PCh. 3 - Prob. 3.39PCh. 3 - Prob. 3.40PCh. 3 - Prob. 3.41PCh. 3 - Prob. 3.42PCh. 3 - Prob. 3.43PCh. 3 - Prob. 3.44PCh. 3 - Prob. 3.45PCh. 3 - Prob. 3.46PCh. 3 - Prob. 3.47PCh. 3 - Prob. 3.48PCh. 3 - Prob. 3.49PCh. 3 - Prob. 3.50PCh. 3 - Prob. 3.51PCh. 3 - Prob. 3.52PCh. 3 - Prob. 3.53PCh. 3 - Prob. 3.54PCh. 3 - Prob. 3.55PCh. 3 - Prob. 3.56PCh. 3 - Prob. 3.57PCh. 3 - Prob. 3.58PCh. 3 - Prob. 3.59PCh. 3 - Prob. 3.60PCh. 3 - Prob. 3.61PCh. 3 - Prob. 3.62PCh. 3 - Prob. 3.63PCh. 3 - Prob. 3.64PCh. 3 - Prob. 3.65PCh. 3 - Prob. 3.66PCh. 3 - Prob. 3.67PCh. 3 - Prob. 3.68PCh. 3 - Prob. 3.69PCh. 3 - Prob. 3.70PCh. 3 - Prob. 3.71PCh. 3 - Prob. 3.72PCh. 3 - Prob. 3.73PCh. 3 - Prob. 3.74PCh. 3 - Prob. 3.75PCh. 3 - Prob. 3.76PCh. 3 - Prob. 3.77PCh. 3 - Prob. 3.78PCh. 3 - Prob. 3.79PCh. 3 - Prob. 3.80PCh. 3 - Prob. 3.81PCh. 3 - Prob. 3.82PCh. 3 - Prob. 3.83PCh. 3 - Prob. 3.84PCh. 3 - Prob. 3.85PCh. 3 - Prob. 3.86PCh. 3 - Prob. 3.87PCh. 3 - Prob. 3.88PCh. 3 - Prob. 3.89PCh. 3 - Prob. 3.90PCh. 3 - Prob. 3.91PCh. 3 - Prob. 3.92PCh. 3 - Prob. 3.93PCh. 3 - Prob. 3.94PCh. 3 - Prob. 3.95PCh. 3 - Prob. 3.96PCh. 3 - Prob. 3.97PCh. 3 - Prob. 3.98PCh. 3 - Prob. 3.99P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- There is an 500g container made out of aluminum holding 300g of water. The Water and Aluminum have reached thermal equilibrium at 40 degrees Celsius. A 200g block of iron at a temperature of 0 degrees Celsius is later dropped into the water. Using the specific heat for water=4180J/kg/C. The specific heat for aluminum is 900 J/kg/C. The specific heat for iron is 450 J/kg/C. The final temperature of the three materials will be degrees celsius. The thermal energy of the water changes by Joules. (give an amount and include a + if it increases and a - if it decreases) The thermal energy of the aluminum changes by Joules. (give an amount and include a + if it increases and a - if it decreases) The thermal energy of the iron changes by Joules. (give an amount and unit and include a + if it increases and a - if the value decreases)arrow_forward.A kilogram of Argon gas( MW= 40 kg/kmol, k=5/3) is in a piston cylinder set-up. Initially, it has pressure of 30kPa and volume of 0.2m3 and expanded to 20 kPa due to heat transfer. If the process is said to be isovolumic, find initial and final temperatures.arrow_forwardIt takes 15 minutes to warm up from 10 C to 20 C in a room whose temperature is 30 C. Assuming Newton's law of cooling, how long would it takes to warm up from 10 C to 25 C?arrow_forward
- An insulated cylinder fitted with a movable piston to maintain constant pressure initially contains 100 g of ice at -10 C. Heat is supplied to the contents at a constant rate by a 100 W heater. Make a graph showing temperature of the cylinder contents as a function of time starting at t = 0, when the temperature is -10 C and ending when the temperature is 110 C. Let c = 2.0 kJ/kg Kfor specific heat of ice from -10 to 0 C and of the steam from 100 to 110 C. The specific heat of water between 0 C and 100 C is c = 4.18 X 103 J/kg K. The value of Lv = 2257 X 103 J/ kg and Lf = 333.5 X 103 J/kg.arrow_forwardThe volume and temperature of a gas at the beginning of expansion are 0.0056m3 and 183°C, respectively; at the end of expansion the values are 0.0238 m3 and 22°C, respectively. Assuming expansion follows the law PV^n=C, find the value of n.arrow_forwardAs shown in the figure below, 0.1 kg of water is contained within a piston- cylinder assembly at 100°C (Sate 1). The piston has a mass of 101.94 kg and is free to move smoothly in the cylinder. Atmospheric pressure, 100 kPa, is acting on the top of the piston. Heat is added in a process until the temperature is 500°C (State 2). Answer the following: (a) Calculate the magnitude and direction of the work and heat transfer in kJ.arrow_forward
- One kg. of gas is confined to a constant volume tank. Initial pressure and volume are 4 0.21m3 respectively. When a heat energy of 82 kJ is supplied to the system, the final temperature of the gas becomes 127 degrees C. Find (a) Work done. (b) Change in internal energy. (c) Specific heat at constant volume. Assume, R=300 Nm/kgK.arrow_forwardSolve it correctly please. Iarrow_forwardPlease solve this problemarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Principles of Heat Transfer (Activate Learning wi...Mechanical EngineeringISBN:9781305387102Author:Kreith, Frank; Manglik, Raj M.Publisher:Cengage Learning
Principles of Heat Transfer (Activate Learning wi...
Mechanical Engineering
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Cengage Learning
First Law of Thermodynamics, Basic Introduction - Internal Energy, Heat and Work - Chemistry; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=NyOYW07-L5g;License: Standard youtube license