FUND OF ENG THERMODYN(LLF)+WILEYPLUS
9th Edition
ISBN: 9781119391777
Author: MORAN
Publisher: WILEY
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Chapter 3, Problem 3.24P
To determine
Show work area on the pressure versus volume diagram and indicate work is done by or on the water vapor.
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3) From an initial state where the pressure is p1, the temperature is T1, and the volume is V1, water vapor contained in a piston-cylinder assembly undergoes each of the following processes:
Process 1–2: Constant‐temperature to p2= 2p1
Process 1–3: Constant volume to p3= 2p1
Process 1–4: Constant pressure to V4= 2V1
Process 1–5: Constant temperature to V5= 2V1
On a p–V diagram, sketch each process, identify the work by an area on the diagram, and indicate whether the work is done by, or on, the water vapor.
1Kg of water contained in a piston-cylinder assembly undergoes five processes in series as follows:
Process 1-2: constant pressure heating at 10 bar from saturated vapor
Process 2-3: constant volume cooling to P; = 5 bar and T; = 180°C
Process 3-4: constant pressure compression to x=0.45
Process 4-5: constant volume heating to Ps = P1
Process 5-1: constant pressure heating to saturated vapor
a. Sketch the above processes on both T-v and P-v diagrams
b. Find quality at point 5, and the work done in each process
Carbon dioxide (CO2) contained within a piston cylinder undergoes three
processes in series:
=
p1 10 bar, V₁ = 0.25 m³, to V₂ = 2.3 m³ during
Process 12: Expansion from
which the pressure-volume relationship is pV = constant
Process 23: Constant volume heating from state 2 to state 3 where p3 = 10 bar
Process 31: Constant pressure compression to the initial state.
Sketch (don't have to use a computer) the process in series on a pV diagram (p on y-axis, V
on x-asix) and evaluate the moving boundary work for each process.
Chapter 3 Solutions
FUND OF ENG THERMODYN(LLF)+WILEYPLUS
Ch. 3 - Prob. 3.1ECh. 3 - Prob. 3.2ECh. 3 - Prob. 3.3ECh. 3 - Prob. 3.4ECh. 3 - Prob. 3.6ECh. 3 - Prob. 3.7ECh. 3 - Prob. 3.8ECh. 3 - Prob. 3.9ECh. 3 - Prob. 3.10ECh. 3 - Prob. 3.11E
Ch. 3 - Prob. 3.12ECh. 3 - Prob. 3.13ECh. 3 - Prob. 3.1CUCh. 3 - Prob. 3.2CUCh. 3 - Prob. 3.3CUCh. 3 - Prob. 3.4CUCh. 3 - Prob. 3.5CUCh. 3 - Prob. 3.6CUCh. 3 - Prob. 3.7CUCh. 3 - Prob. 3.8CUCh. 3 - Prob. 3.9CUCh. 3 - Prob. 3.10CUCh. 3 - Prob. 3.11CUCh. 3 - Prob. 3.12CUCh. 3 - Prob. 3.13CUCh. 3 - Prob. 3.14CUCh. 3 - Prob. 3.15CUCh. 3 - Prob. 3.16CUCh. 3 - Prob. 3.17CUCh. 3 - Prob. 3.18CUCh. 3 - Prob. 3.19CUCh. 3 - Prob. 3.20CUCh. 3 - Prob. 3.21CUCh. 3 - Prob. 3.22CUCh. 3 - Prob. 3.23CUCh. 3 - Prob. 3.24CUCh. 3 - Prob. 3.25CUCh. 3 - Prob. 3.26CUCh. 3 - Prob. 3.27CUCh. 3 - Prob. 3.28CUCh. 3 - Prob. 3.29CUCh. 3 - Prob. 3.30CUCh. 3 - Prob. 3.31CUCh. 3 - Prob. 3.32CUCh. 3 - Prob. 3.33CUCh. 3 - Prob. 3.34CUCh. 3 - Prob. 3.35CUCh. 3 - Prob. 3.36CUCh. 3 - Prob. 3.37CUCh. 3 - Prob. 3.38CUCh. 3 - Prob. 3.39CUCh. 3 - Prob. 3.40CUCh. 3 - Prob. 3.41CUCh. 3 - Prob. 3.42CUCh. 3 - Prob. 3.43CUCh. 3 - Prob. 3.44CUCh. 3 - Prob. 3.45CUCh. 3 - Prob. 3.46CUCh. 3 - Prob. 3.47CUCh. 3 - Prob. 3.48CUCh. 3 - Prob. 3.49CUCh. 3 - Prob. 3.50CUCh. 3 - Prob. 3.51CUCh. 3 - Prob. 3.52CUCh. 3 - Prob. 3.1PCh. 3 - Prob. 3.2PCh. 3 - Prob. 3.3PCh. 3 - Prob. 3.4PCh. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10PCh. 3 - Prob. 3.11PCh. 3 - Prob. 3.12PCh. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - Prob. 3.16PCh. 3 - Prob. 3.17PCh. 3 - Prob. 3.18PCh. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Prob. 3.23PCh. 3 - Prob. 3.24PCh. 3 - Prob. 3.25PCh. 3 - Prob. 3.26PCh. 3 - Prob. 3.27PCh. 3 - Prob. 3.28PCh. 3 - Prob. 3.29PCh. 3 - Prob. 3.30PCh. 3 - Prob. 3.31PCh. 3 - Prob. 3.32PCh. 3 - Prob. 3.33PCh. 3 - Prob. 3.34PCh. 3 - Prob. 3.35PCh. 3 - Prob. 3.36PCh. 3 - Prob. 3.37PCh. 3 - Prob. 3.38PCh. 3 - Prob. 3.39PCh. 3 - Prob. 3.40PCh. 3 - Prob. 3.41PCh. 3 - Prob. 3.42PCh. 3 - Prob. 3.43PCh. 3 - Prob. 3.44PCh. 3 - Prob. 3.45PCh. 3 - Prob. 3.46PCh. 3 - Prob. 3.47PCh. 3 - Prob. 3.48PCh. 3 - Prob. 3.49PCh. 3 - Prob. 3.50PCh. 3 - Prob. 3.51PCh. 3 - Prob. 3.52PCh. 3 - Prob. 3.53PCh. 3 - Prob. 3.54PCh. 3 - Prob. 3.55PCh. 3 - Prob. 3.56PCh. 3 - Prob. 3.57PCh. 3 - Prob. 3.58PCh. 3 - Prob. 3.59PCh. 3 - Prob. 3.60PCh. 3 - Prob. 3.61PCh. 3 - Prob. 3.62PCh. 3 - Prob. 3.63PCh. 3 - Prob. 3.64PCh. 3 - Prob. 3.65PCh. 3 - Prob. 3.66PCh. 3 - Prob. 3.67PCh. 3 - Prob. 3.68PCh. 3 - Prob. 3.69PCh. 3 - Prob. 3.70PCh. 3 - Prob. 3.71PCh. 3 - Prob. 3.72PCh. 3 - Prob. 3.73PCh. 3 - Prob. 3.74PCh. 3 - Prob. 3.75PCh. 3 - Prob. 3.76PCh. 3 - Prob. 3.77PCh. 3 - Prob. 3.78PCh. 3 - Prob. 3.79PCh. 3 - Prob. 3.80PCh. 3 - Prob. 3.81PCh. 3 - Prob. 3.82PCh. 3 - Prob. 3.83PCh. 3 - Prob. 3.84PCh. 3 - Prob. 3.85PCh. 3 - Prob. 3.86PCh. 3 - Prob. 3.87PCh. 3 - Prob. 3.88PCh. 3 - Prob. 3.89PCh. 3 - Prob. 3.90PCh. 3 - Prob. 3.91PCh. 3 - Prob. 3.92PCh. 3 - Prob. 3.93PCh. 3 - Prob. 3.94PCh. 3 - Prob. 3.95PCh. 3 - Prob. 3.96PCh. 3 - Prob. 3.97PCh. 3 - Prob. 3.98PCh. 3 - Prob. 3.99P
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- 3. The closed piston-cylinder assembly shown contains Ammonia. The piston moves between two sets of stops. When the piston is against the left stop, the enclosed volume is V₁ 1.0 m³ and when the piston is against the right stop the enclosed volume is V₁ = 2.5 m³. Atmospheric pressure is 1 bar. Heat is added so that the piston moves slowly to the right. Sketch all processes on a p - v diagram and determine the net work done during each process. State 1: The piston is in contact with the left stop and P₁ = 0.8 bar State 2: The piston first leaves the left stop State 3: The piston first reaches the right stop State 4: The pressure in the piston increases to P₂ = 5 bar 0 Ammonia 0arrow_forward2.15 Air undergoes two processes in series! Process 1-2: polytropic compression, with n = 1.3, from pi= 100 kPa. v₁ = 0.04 m³/kg to 1/2 = 0.02 m³/kg Process 2-3: constant-pressure process to 3 = V₁ Sketch the processes on a p-v diagram and determine the total work per unit mass of air, in kJ/kg.arrow_forwardA rigid tank of volume 10 m³ initially contains saturated water vapor at a temperature of 120 °C. Steam at a pressure 1.2 MPa and a temperature of 400 °C enters the tank through a valve in steam line that is connected to the tank until the final pressure in the tank is 800 kPa, at which time the temperature is 200 °C. All kinetic and potential energy effects can be neglected. A schematic of the problem and properties at all state points except state 1 are shown in the figure below. All of the properties at state 2 and the inlet state i are provided on the figure. Initial State in Tank T₁-120 °C, Sat. vapor u₁=? kJ/kg V₁=? m³/kg Pi=1.2 MPa, Ti-400 °C hi=3261.3 kJ/kg V=10 m³ Final State in Tank T₂-200 °C, P₂-800 kPa u₂=2631.1 kJ/kg v₂=0.26088 m³/kg Qoutarrow_forward
- A gas contained within a piston-cylinder assembly undergoes three processes in series: Process 1-2: Constant volume from p₁ = 1 bar, V₁ = 4 m³ to state 2, where p2 = 2 bar. Process 2-3: Compression to V3 = 2 m³, during which the pressure-volume relationship is pV = constant. Process 3-4: Constant pressure to state 4, where V4 = 1 m³. Sketch the processes in series p-V coordinates and evaluate the work for each process, in kJ. Hint: Draw all the processes neatly on P-V diagram. Denote the states 1-4. Do not forget to add arrows.arrow_forwardCharles' law states that If the pressure on a particular quantity of gas is held constant, then, with any change of state, the volume will vary directly as the absolute temperature. If the temperature on a particular quantity of gas is held constant, then, with any change of state, the volume will vary directly as pressure. If the temperature on a particular quantity of gas is held constant, then, with any change of state, the volume will varies inversely as pressure. It is a composite property applicable to all fluids, known as Heat Energy Enthalpyarrow_forwardplease be cleararrow_forward
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