For the two−input NMOS NOR logic gate in Figure 3.46 in the text, the transistor parameters are V T N 1 = V T N 2 = 0.6 V , λ 1 = λ 2 = 0 , and k ′ n 1 = k ′ n 2 = 120 μ A/V 2 . The drain resistor is R D = 50 k Ω (a) Determine the width−to−length ratios of the transistors so that V O = 1.15 V when V 1 = V 2 = 5 V . Assume that ( W / L ) 1 = ( W / L ) 2 . (b) Using the results of part (a), find V O when V 1 = 5 V and V 2 = 0.2 V .
For the two−input NMOS NOR logic gate in Figure 3.46 in the text, the transistor parameters are V T N 1 = V T N 2 = 0.6 V , λ 1 = λ 2 = 0 , and k ′ n 1 = k ′ n 2 = 120 μ A/V 2 . The drain resistor is R D = 50 k Ω (a) Determine the width−to−length ratios of the transistors so that V O = 1.15 V when V 1 = V 2 = 5 V . Assume that ( W / L ) 1 = ( W / L ) 2 . (b) Using the results of part (a), find V O when V 1 = 5 V and V 2 = 0.2 V .
Solution Summary: The author calculates the width to length ratio for an NMOS NOR circuit for the given transistor parameters and for a given input-output combination.
For the two−input NMOS NOR logic gate in Figure 3.46 in the text, the transistor parameters are
V
T
N
1
=
V
T
N
2
=
0.6
V
,
λ
1
=
λ
2
=
0
, and
k
′
n
1
=
k
′
n
2
=
120
μ
A/V
2
. The drain resistor is
R
D
=
50
k
Ω
(a) Determine the width−to−length ratios of the transistors so that
V
O
=
1.15
V
when
V
1
=
V
2
=
5
V
. Assume that
(
W
/
L
)
1
=
(
W
/
L
)
2
. (b) Using the results of part (a), find
V
O
when
V
1
=
5
V
and
V
2
=
0.2
V
.
Assume that a building manager instructed you to install a water heater. The specs on the water heater nameplate reveals the following 240V, 2PH, 60HZ, 5.7KW. The manager insisted for the installation to be done with 10 AWG copper THWN-2 conductor, the length of run is 1200 FT away from the service panel. Calculate the voltage after the installation.
Please confirm that my solution is correct, especially the block diagram. Please DRAW (not type) what the block diagram would look like if it's incorrect.
thank you
use this code on the bottom to answer the question in the photo
clc; clearvars;
% Read the file [y, Fs] = audioread('106miles.wav'); N = length(y); Nfft = 2^nextpow2(N); dt = 1/Fs; t = (0:dt:(N-1)*dt)'; % Ensure t is a column vector y = y - mean(y); % Remove DC component (if not already zero-mean)
% Carrier signal (25 kHz) fc = 25000; % Carrier frequency in Hz carrier = cos(2 * pi * fc * t);
% DSB-SC Modulation modulated_signal = y .* carrier;
% Plot Time Domain Signal figure; subplot(2,1,1); plot(t, y); title('Original Signal (Time Domain)'); xlabel('Time (s)'); ylabel('Amplitude');
subplot(2,1,2); plot(t, modulated_signal); title('DSB-SC Modulated Signal (Time Domain)'); xlabel('Time (s)'); ylabel('Amplitude');
% Frequency Domain (FFT) Y = fft(y, Nfft) / Nfft; Modulated_Y = fft(modulated_signal, Nfft) / Nfft; f = Fs * (0:(Nfft/2)) / Nfft; % Frequency vector
% Plot Frequency Domain Signal figure; subplot(2,1,1); plot(f, abs(Y(1:Nfft/2+1))); title('Original Signal…
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