Total valence electrons found in cation H 3 C ⊕ should be determined. Concept introduction: A carbocation is a planar system and therefore s p 2 hybridized with vacant unhybridized p -orbital. There are three s p 2 and 1 s overlaps; each shows that s p 2 hybrid orbital with one electron overlaps with 1 s orbital of hydrogen that has electron in antiparallel spin so that a stable sigma bond formation may occur as illustrated below:

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Chapter 3, Problem 10CTQ

Interpretation Introduction

Interpretation: Total valence electrons found in cation H3C⊕ should be determined.

Concept introduction: A carbocation is a planar system and therefore sp2 hybridized with vacant unhybridized p -orbital. There are three sp2 and 1s overlaps; each shows that sp2 hybrid orbital with one electron overlaps with 1s orbital of hydrogen that has electron in antiparallel spin so that a stable sigma bond formation may occur as illustrated below:

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Chapter 3, Problem 10CTQ

Interpretation Introduction

Interpretation: Total valence electrons found in cation H3C⊕ should be determined.

Concept introduction: A carbocation is a planar system and therefore sp2 hybridized with vacant unhybridized p -orbital. There are three sp2 and 1s overlaps; each shows that sp2 hybrid orbital with one electron overlaps with 1s orbital of hydrogen that has electron in antiparallel spin so that a stable sigma bond formation may occur as illustrated below:

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Answer 3

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Chapter 3, Problem 10CTQ

Interpretation Introduction

Interpretation: Total valence electrons found in cation H3C⊕ should be determined.

Concept introduction: A carbocation is a planar system and therefore sp2 hybridized with vacant unhybridized p -orbital. There are three sp2 and 1s overlaps; each shows that sp2 hybrid orbital with one electron overlaps with 1s orbital of hydrogen that has electron in antiparallel spin so that a stable sigma bond formation may occur as illustrated below:

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Answer 4

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Chapter 3, Problem 10CTQ

Interpretation Introduction

Interpretation: Total valence electrons found in cation H3C⊕ should be determined.

Concept introduction: A carbocation is a planar system and therefore sp2 hybridized with vacant unhybridized p -orbital. There are three sp2 and 1s overlaps; each shows that sp2 hybrid orbital with one electron overlaps with 1s orbital of hydrogen that has electron in antiparallel spin so that a stable sigma bond formation may occur as illustrated below:

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Answer 5

Chapter 3, Problem 10CTQ

Interpretation Introduction

Interpretation: Total valence electrons found in cation H3C⊕ should be determined.

Concept introduction: A carbocation is a planar system and therefore sp2 hybridized with vacant unhybridized p -orbital. There are three sp2 and 1s overlaps; each shows that sp2 hybrid orbital with one electron overlaps with 1s orbital of hydrogen that has electron in antiparallel spin so that a stable sigma bond formation may occur as illustrated below:

Answer 6

Chapter 3, Problem 10CTQ

Interpretation Introduction

Interpretation: Total valence electrons found in cation H3C⊕ should be determined.

Concept introduction: A carbocation is a planar system and therefore sp2 hybridized with vacant unhybridized p -orbital. There are three sp2 and 1s overlaps; each shows that sp2 hybrid orbital with one electron overlaps with 1s orbital of hydrogen that has electron in antiparallel spin so that a stable sigma bond formation may occur as illustrated below:

Answer 7

Chapter 3, Problem 10CTQ

Interpretation Introduction

Interpretation: Total valence electrons found in cation H3C⊕ should be determined.

Concept introduction: A carbocation is a planar system and therefore sp2 hybridized with vacant unhybridized p -orbital. There are three sp2 and 1s overlaps; each shows that sp2 hybrid orbital with one electron overlaps with 1s orbital of hydrogen that has electron in antiparallel spin so that a stable sigma bond formation may occur as illustrated below:

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Ch. 3 - Prob. 1CTQ Ch. 3 - What neutral atom is represented by the electron...Ch. 3 - Prob. 3CTQ Ch. 3 - Consider any one of the four identical hybrid...Ch. 3 - Prob. 5CTQ Ch. 3 - Prob. 6CTQ Ch. 3 - Prob. 7CTQ Ch. 3 - Prob. 8CTQ Ch. 3 - Prob. 9CTQ Ch. 3 - Prob. 10CTQ

Solution Summary: The author explains that three valence electrons are located in p of carbon in a carbocation.

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