Concept explainers
To Explain: A secondary rainbow is dimmer than the primary bow.
Answer to Problem 47A
After the double reflection, ray of light loses its energy. So, secondary rainbow is dimmer than the primary bow.
Explanation of Solution
Introduction: Angle of reflection is equals to angle of incidence. Also, the law of reflection applies to both, totally reflected waves and partially reflected.
Explanation: Rainbow is a spectacular illustration of dispersion. A secondary rainbow develops when light entering a raindrop undergoes two internal reflections instead of just one. Also, a secondary rainbow is dimmer than the primary bow because intensity of the light is diminished by the extra internal reflection.
Conclusion: A secondary rainbow is not as bright as a primary rainbow.
Chapter 29 Solutions
Conceptual Physics: The High School Physics Program
Additional Science Textbook Solutions
Concepts of Genetics (12th Edition)
Chemistry: Structure and Properties (2nd Edition)
Cosmic Perspective Fundamentals
Chemistry
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Biology: Life on Earth with Physiology (11th Edition)
- T1. Calculate what is the received frequency when the car drives away from the radar antenna at a speed v of a) 1 m/s ( = 3.6 km/h), b) 10 m/s ( = 36 km/h), c) 30 m /s ( = 108 km/h) . The radar transmission frequency f is 24.125 GHz = 24.125*10^9 Hz, about 24 GHz. Speed of light 2.998 *10^8 m/s.arrow_forwardNo Chatgpt please will upvotearrow_forwardNo Chatgpt please will upvotearrow_forward
- No Chatgpt pleasearrow_forward3. A measurement taken from the UW Jacobson Observatory (Latitude: 47.660503°, Longitude: -122.309424°, Altitude: 220.00 feet) when its local sidereal time is 120.00° makes the following observations of a space object (Based on Curtis Problems 5.12 + 5.13): Azimuth: 225.00° Azimuth rate: 2.0000°/s. Elevation: 75.000° Elevation rate: -0.5000°/s Range: 1500.0 km Range rate: -1.0000 km/s a. What are the r & v vectors (the state vector) in geocentric coordinates? (Answer r = [-2503.47 v = [17.298 4885.2 5.920 5577.6] -2.663]) b. Calculate the orbital elements of the satellite. (For your thoughts: what type of object would this be?) (Partial Answer e = 5.5876, 0=-13.74°) Tip: use Curtis algorithms 5.4 and 4.2.arrow_forwardConsider an isotope with an atomic number of (2(5+4)) and a mass number of (4(5+4)+2). Using the atomic masses given in the attached table, calculate the binding energy per nucleon for this isotope. Give your answer in MeV/nucleon and with 4 significant figures.arrow_forward
- A: VR= 2.4 cm (0.1 V/cm) = 0.24 V What do Vector B an C represent and what are their magnitudesarrow_forward4. Consider a cubesat that got deployed below the ISS and achieved a circular orbit of 410 km altitude with an inclination of 51.600°. What is the spacing, in kilometers, between successive ground tracks at the equator: a. Ignoring J2 (Earth's oblateness) effects b. Accounting for J2 effects c. Compare the two results and comment [Partial Answer: 35.7km difference]arrow_forwardplease solve and explainarrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON