The characteristics of steroid hormones in the mechanism of action that shares with the thyroxine have to be explained. Concept Introduction: Hormones: Hormones are chemical messengers which are secreted by the cell in endocrine system and are transported along the blood to stimulate the target cells having the corresponding receptors. Hormones are of three types, 1. Amino acid derivatives: It is a derivative of an amino acid formed by the reaction at the side chain functional group , carboxylic acid group, amino group or by the replacement of a hydrogen atom by heteroatom. 2. Polypeptides: Polypeptides are organic polymers having several amino acids attached to each other in a chain. 3. Steroid: Steroids are a type of organic compound having a molecular structure with four rings connected to each other. Thyroxine molecule and all the steroid hormones is nonpolar compound so they enter the cell membrane directly by diffusion.

Question

Want to see the full answer?

Answer 1

Question

Chapter 28, Problem 28.85CP

Interpretation Introduction

Interpretation:

The characteristics of steroid hormones in the mechanism of action that shares with the thyroxine have to be explained.

Concept Introduction:

Hormones: Hormones are chemical messengers which are secreted by the cell in endocrine system and are transported along the blood to stimulate the target cells having the corresponding receptors.

Hormones are of three types,

1. Amino acid derivatives: It is a derivative of an amino acid formed by the reaction at the side chain functional group, carboxylic acid group, amino group or by the replacement of a hydrogen atom by heteroatom.

2. Polypeptides: Polypeptides are organic polymers having several amino acids attached to each other in a chain.

3. Steroid: Steroids are a type of organic compound having a molecular structure with four rings connected to each other.

Thyroxine molecule and all the steroid hormones is nonpolar compound so they enter the cell membrane directly by diffusion.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

The preferred substrate is T because the enzyme half-saturates at 7.00 mM for T, but requires 28.0 mM for U, and 112 mM for S. b Question Content Area The rate constant k 2 with substrate S is 9.60×107 sec-1, with substrate T, k 2 = 6.00×104 sec-1, and with substrate U, k 2 = 2.40×106 sec-1. Calculate the catalytic efficiency with S, T, and U. Catalytic efficiency with S = Catalytic efficiency with T = Catalytic efficiency with U = Does enzyme A use substrate S, substrate T, or substrate U with greater catalytic efficiency?

Fumerase catalyzes the conversion of fumerate to malate. fumerate + H2O ⇋ malate The turnover number, kcat, for fumerase is 8.00×102 sec-1. The Km of this enzyme for fumerate is 5.00×10-3 μmol mL-1. a In an experiment using 2.00×10-3 μmol·mL-1, what is Vmax?

Suppose you wanted to make a buffer of exactly pH 7.00 using KH2PO4 and Na2HPO4. If the final solution was 0.18 M in KH2PO4, you would need 0.25 M Na2HPO4. Now assume you wish to make a buffer at the same pH, using the same substances, but want the total phosphate molarity ([HPO42−]+[H2PO−4]) to equal 0.20 M. What concentration of the Na2HPO4 would be required?