Chapter 25.2, Problem 14LC

(a)

Interpretation Introduction

Interpretation: To complete the nuclear reaction and identify the product.

Concept Introduction: The process which involves the formation of more than one nuclide via a collision between two nuclei or between one nucleus and a subatomic particle, is known as a nuclear reaction.

Answer to Problem 14LC

The complete nuclear reaction is as follows:

  $\text{A}\text{l}+\text{H}\text{e}\to \text{S}\text{i}+\text{p}$

Explanation of Solution

The given nuclear reaction depicts the alpha decay that is as follows:

  $\text{A}\text{l}+\text{H}\text{e}\to \text{S}\text{i}+\text{p}$

The missing particle is a proton, i.e., $\text{p}$ .

(b)

Interpretation Introduction

Interpretation: To complete the nuclear reaction and identify the product.

Concept Introduction: The process which involves the formation of more than one nuclide via a collision between two nuclei or between one nucleus and a subatomic particle, is known as a nuclear reaction.

Answer to Problem 14LC

The complete nuclear reaction is as follows:

  $\text{B}\text{i}\to \text{H}\text{e}+\text{T}\text{l}$

Explanation of Solution

The given nuclear reaction depicts the alpha decay that is as follows:

  $\text{B}\text{i}\to \text{H}\text{e}+\text{T}\text{l}$

This nuclear reaction depicts alpha emission.

It increases the neutron-to-proton ratio, thereby, increasing the stability of the nucleus.

The missing particle is $\text{T}\text{l}$ .

(c)

Interpretation Introduction

Interpretation: To complete the nuclear reaction and identify the product.

Concept Introduction: The process which involves the formation of more than one nuclide via a collision between two nuclei or between one nucleus and a subatomic particle, is known as a nuclear reaction.

Answer to Problem 14LC

The complete nuclear reaction is as follows:

  $\text{S}\text{i}\to \text{e}{}^{-}+\text{A}\text{l}$

Explanation of Solution

The given nuclear reaction depicts the beta emission that is as follows:

  $\text{S}\text{i}\to \text{e}{}^{-}+\text{A}\text{l}$

A neutron emits an electron and changes to the proton, this process is known as beta emission.

It increases protons while decreasing the neutron’s number.

The missing particle is $\text{A}\text{l}$ .

(d)

Interpretation Introduction

Interpretation: To complete the nuclear reaction and identify the product.

Concept Introduction: The process which involves the formation of more than one nuclide via a collision between two nuclei or between one nucleus and a subatomic particle, is known as a nuclear reaction.

Answer to Problem 14LC

The complete nuclear reaction is as follows:

  $\text{S}\text{i}\to \text{e}{}^{-}+\text{A}\text{l}$

Explanation of Solution

The given nuclear reaction depicts the positron emission that is as follows:

  $\text{C}\text{u}\to \text{Z}\text{n}+\text{e}$

A positron is a particle having an electron’s mass with a positive charge. In positron emission, a proton is changed to a neutron.

The missing particle is $\text{e}$ .