Interpretation: The question is to find the number of protons, neutrons, and electrons in Iron-59, Uranium-235, and Chromium-52.
Concept Introduction: The
Answer to Problem 101A
The number of protons, neutrons, and electrons in Iron-59 are 26, 33, and 26 respectively.
The number of protons, neutrons, and electrons in Uranium-235 are 92, 143, and 92 respectively.
The number of protons, neutrons, and electrons in Chromium-52 are 24, 26, and 24 respectively.
Explanation of Solution
Given information:
The isotopes given are Iron-59, Uranium-235, and Chromium-52.
Iron-59:
The atomic number of Iron-59 is 26 and the mass number is 59.
Number of protons = 26
Number of neutrons = 33
Number of neutrons = 26
Uranium-235
The atomic number of Uranium-235 is 92 and the mass number is 143.
Number of protons = 92
Number of neutrons = 143
Number of neutrons = 92
Chromium-52:
The atomic number of Chromium-52 is 24 and the mass number is 26.
Number of protons = 24
Number of neutrons = 26
Number of neutrons = 24
Hence, the number of protons, neutrons, and electrons in Iron-59, Uranium-235, and Chromium-52 are listed above.
Chapter 25 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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- For each of the following, indicate whether the arrow pushes are valid. Do we break any rules via the arrows? If not, indicate what is incorrect. Hint: Draw the product of the arrow and see if you still have a valid structure. a. b. N OH C. H N + H d. e. f. مه N COHarrow_forwardDecide which is the most acidic proton (H) in the following compounds. Which one can be removed most easily? a) Ha Нь b) Ha Нь c) CI CI Cl Ha Ньarrow_forwardProvide all of the possible resonanse structures for the following compounds. Indicate which is the major contributor when applicable. Show your arrow pushing. a) H+ O: b) c) : N :O : : 0 d) e) Оarrow_forward
- Draw e arrows between the following resonance structures: a) b) : 0: :0: c) :0: N t : 0: بار Narrow_forwardDraw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. Cl Substitution will not occur at a significant rate. Explanation Check :☐ O-CH + Х Click and drag to start drawing a structure.arrow_forwardDraw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. Cl C O Substitution will not occur at a significant rate. Explanation Check + O-CH3 Х Click and drag to start drawing a structure.arrow_forward
- ✓ aw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. C Cl HO–CH O Substitution will not occur at a significant rate. Explanation Check -3 ☐ : + D Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Cearrow_forwardPlease correct answer and don't used hand raitingarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
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