EP GENERAL CHEMISTRY-MOD.MASTERINGCHEM.
11th Edition
ISBN: 9780133897340
Author: Petrucci
Publisher: PEARSON CO
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Chapter 24, Problem 24E
Interpretation Introduction
Interpretation:
The reason for the Fe (II) ion in [Fe(H2O)6]2+ to be paramagnetic and in [Fe(CN)6]4- to be diamagnetic needs to be determined.
Concept introduction:
Diamagnetic property of molecule is defined as that when the total spin of paired electrons is zero or when there areno unpaired electrons present in the molecule, whereas, the paramagnetic property of molecule occurs when there is a presence of unpaired electrons which results in the non-zero total spin.
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Students have asked these similar questions
Which is more acidic and why? [Fe(H2O)6]2+ or [Fe(NH3)(H2O)5]2+
Aarange the following in increasing order of acidity and provide reason for same: [Fe(OH2)6]2+, [Al(OH2)6]3+,[Fe(OH2)6]3+.
Draw the octahedral crystal field d orbital splitting diagrams for [Fe(OH2)6] 2+ and [Fe(CN)6] 3. Indicate if the
diagrams are high spin and low spin. give the names of the d-orbitals (dxz, dxy, dzy, dz2, dx2 - y2) label the appropriate
orbital sets eg* and t2g and show how the electrons populate the diagram. (Hint: Pairing energy for 3d orbitals Fe
2+ = 29875 cm-1, Fe 3+ = 19150 cm-1; delta OH for Fe(OH2)6]2+ = 14300 cm-1 and delta OH for [Fe(CN)6]3 - is
35000 cm-1
Chapter 24 Solutions
EP GENERAL CHEMISTRY-MOD.MASTERINGCHEM.
Ch. 24 - Prob. 1ECh. 24 - Prob. 2ECh. 24 - Prob. 3ECh. 24 - Write appropriate formulas for the following. a....Ch. 24 - Prob. 5ECh. 24 - Prob. 6ECh. 24 - Prob. 7ECh. 24 - Prob. 8ECh. 24 - Prob. 9ECh. 24 - Prob. 10E
Ch. 24 - Prob. 11ECh. 24 - Prob. 12ECh. 24 - If A, B, C, and D are four different ligands, a....Ch. 24 - Prob. 14ECh. 24 - Prob. 15ECh. 24 - The structures of four complex ions are given....Ch. 24 - Prob. 17ECh. 24 - Prob. 18ECh. 24 - Prob. 19ECh. 24 - In contrast to the case of Co2+ considered in...Ch. 24 - Prob. 21ECh. 24 - Prob. 22ECh. 24 - Prob. 23ECh. 24 - Prob. 24ECh. 24 - Prob. 25ECh. 24 - Prob. 26ECh. 24 - Prob. 27ECh. 24 - Prob. 28ECh. 24 - Prob. 29ECh. 24 - Prob. 30ECh. 24 - Prob. 31ECh. 24 - Prob. 32ECh. 24 - Prob. 33ECh. 24 - Prob. 34ECh. 24 - Prob. 35ECh. 24 - Prob. 36ECh. 24 - Prob. 37ECh. 24 - Draw dashed and solid wedge diagrams of...Ch. 24 - Prob. 39IAECh. 24 - Prob. 40IAECh. 24 - Prob. 41IAECh. 24 - Prob. 42IAECh. 24 - Prob. 43IAECh. 24 - Prob. 44IAECh. 24 - Prob. 45IAECh. 24 - Prob. 46IAECh. 24 - Prob. 47IAECh. 24 - Prob. 48IAECh. 24 - Prob. 49IAECh. 24 - Prob. 50IAECh. 24 - Prob. 51IAECh. 24 - Prob. 52IAECh. 24 - Prob. 53IAECh. 24 - Prob. 54IAECh. 24 - The compound CoCl22H2O4NH2 may be one of the...Ch. 24 - Prob. 56IAECh. 24 - Provide a valence bond description of the bonding...Ch. 24 - Prob. 58IAECh. 24 - Prob. 59IAECh. 24 - Prob. 60IAECh. 24 - Prob. 61IAECh. 24 - Prob. 62IAECh. 24 - The graph that follows represents the molar...Ch. 24 - Prob. 64FPCh. 24 - Prob. 65FPCh. 24 - The crystal field stabilization energy (CFSE) can...Ch. 24 - In your own words, describe the following terms or...Ch. 24 - Briefly describe each of the following ideas,...Ch. 24 - Prob. 69SAECh. 24 - The oxidation state of Ni in the complex ion...Ch. 24 - Prob. 71SAECh. 24 - Prob. 72SAECh. 24 - Prob. 73SAECh. 24 - Prob. 74SAECh. 24 - Prob. 75SAECh. 24 - The most soluble of the following solids in...Ch. 24 - Prob. 77SAECh. 24 - Write appropriate formulas for the following...Ch. 24 - Prob. 79SAECh. 24 - Prob. 80SAECh. 24 - Prob. 81SAECh. 24 - Prob. 82SAECh. 24 - Prob. 83SAECh. 24 - Prob. 84SAE
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- Iron(II) forms a complex in hemoglobin. Two of the possibilities are [Fe(H2O)6]2+ and [Fe(CN)6]4– (a) [Fe(H2O)6]2+ and [Fe(CN)6]4– should have the same geometry. What is this coordination environment? Draw it please. (b) For both [Fe(H2O)6]2+ and [Fe(CN)6]4–, draw an energy diagram showing orbital splitting (c) Predict the number of unpaired electrons(d) Identify the ion as low spin or high spin.(e) Is either ion paramagnetic?(f) What would the color of each form of these forms ofhemoglobin?arrow_forwarddraw the structure of [Fe(NH3)3(OH2)3][PtCl4]arrow_forwardexplain why the formation constant of [Fe(bpy)3]^2+ from [Fe(H2O)6]^2+ might be expected to be larger than that of [Fe(NH3)6]^2+ from [Fe(H2O)6]^2+. (bpy is the nitrogen donor bipyridine)arrow_forward
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