A nonconducting solid sphere has a uniform volume charge density ρ . Let r → be the vector from the center of the sphere to a general point P within the sphere. (a) Show that the electric field at P is given by E → = ρ r → / 3 ε 0 . (Note that the result is independent of the radius of the sphere.) (b) A spherical cavity is hollowed out of the sphere, as shown in Fig. 23-60. Using superposition concepts, show that the electric field at all points within the cavity is uniform and equal to E → = ρ a → / 3 ε 0 , where a → is the position vector from the center of the sphere to the center of the cavity. Figure 23-60 Problem 73.
A nonconducting solid sphere has a uniform volume charge density ρ . Let r → be the vector from the center of the sphere to a general point P within the sphere. (a) Show that the electric field at P is given by E → = ρ r → / 3 ε 0 . (Note that the result is independent of the radius of the sphere.) (b) A spherical cavity is hollowed out of the sphere, as shown in Fig. 23-60. Using superposition concepts, show that the electric field at all points within the cavity is uniform and equal to E → = ρ a → / 3 ε 0 , where a → is the position vector from the center of the sphere to the center of the cavity. Figure 23-60 Problem 73.
A nonconducting solid sphere has a uniform volume charge density ρ. Let
r
→
be the vector from the center of the sphere to a general point P within the sphere. (a) Show that the electric field at P is given by
E
→
=
ρ
r
→
/
3
ε
0
. (Note that the result is independent of the radius of the sphere.) (b) A spherical cavity is hollowed out of the sphere, as shown in Fig. 23-60. Using superposition concepts, show that the electric field at all points within the cavity is uniform and equal to
E
→
=
ρ
a
→
/
3
ε
0
, where
a
→
is the position vector from the center of the sphere to the center of the cavity.
Imagine you are out for a stroll on a sunny day when you encounter a lake. Unpolarized light from the sun is reflected off the lake into your eyes. However, you notice when you put on your vertically polarized sunglasses, the light reflected off the lake no longer reaches your eyes. What is the angle between the unpolarized light and the surface of the water, in degrees, measured from the horizontal? You may assume the index of refraction of air is nair=1 and the index of refraction of water is nwater=1.33 . Round your answer to three significant figures. Just enter the number, nothing else.
Deduce what overvoltage is like in reversible electrodes.
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
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