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A nonconducting solid sphere has a uniform volume charge density ρ. Let
Figure 23-60 Problem 73.
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- 2) In Fig. 23-45, a small circular hole of radius R = 1.80 cm has een cut in the middle of an infinite, flat, nonconducting surface hat has uniform charge density o=4.50 pC/m². A z axis, with its rigin at the hole's center, is perpendicular to the surface. In unit- ector notation, what is the electric field at point P at z = 2.56 cm? Hint: See Eq. 22-26 and use superposition.) X X X X X X X X X X X X X X X X X XX X X X X 15 X XXX Z Figure 23-45 X X X X X X X X X X X X X X X X X X X X X X X X X X X Xarrow_forwardAn infinitely long, solid insulating cylinder with radius Ra is placed concentric within a conducting cylindrical shell of inner radius R₂ and outer radius Re. The inner cylinder has a uniform volume charge density +lpl, and the outer cylinder has a net linear charge density of -3121. Assume IpR²l> 132] for all parts.arrow_forwardPart A Uniform plane of charge. Charge is distributed uniformly over a large square plane of side l, as shown in the figure(Figure 1). The charge per unit Determine the electric field at a point Pa distance z above the center of the plane, in the limit l → 0. [Hint. Divide the plane into long narrow strips of width dy, and use the result of Example 21-11 in the textbook; then sum the fields due to each strip to get the total field at P] • (C/m²)is area is o. Express your answer in terms of the variables o, z, and appropriate constants. Figure < 1 of 1 ν ΑΣφ dE dE E = dE, P dy Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remainingarrow_forward
- Consider a charged sphere of radius R having uniform volume charge density. Electric field at point e,r, (d) none of thesearrow_forward•34 In Fig. 23-45, a small circular hole of radius R = 1.80 cm has been cut in the middle of an infinite, flat, nonconducting surface that has uniform charge density o = 4.50 pC/m?. A z axis, with its origin at the hole's center, is perpendicular to the surface. In unit- vector notation, what is the electric field at point Pat z = 2.56 cm? (Hint: See Eq. 22-26 and use superposition.) Figure 23-45 Problem 34.arrow_forward13/20 13) The total negative charge carried by a solid conducting sphere of radius R is -Q. This sphere is surrounded by an insulating shell of inner radius R and outer radius 2R. The uniform charge density of the insulating shell is p. What is the value of p that will make the net charge of the entire system zero? Find the magnitude of the electric field for Rarrow_forwardFigure 22-53 Problem 30. *31 SSM ILW www In Fig. 22-54, a nonconducting rod of length L = 8.15 cm has a charge -q = -4.23 fC uniformly distributed along its length. (a) What is the linear charge density of the rod? What are the (b) magni- tude and (c) direction (relative to the positive direction of the x axis) of the electric field produced at point P, at distance a = 12.0 cm from the rod? What is the electric field magnitude produced at distance a =50 m by (d) the rod and (e) a particle of charge -q = -4.23 fC that we use to replace the rod? (At that distance, the rod "looks" like a particle.) -4 -x- Figure 22-54 Problem 31.arrow_forward(a) Determine the electric field intensity E caused by a spherical cloud of electrons in free space with a volume charge density p=-P for 0≤R≤a (both P, and a are positive) and p=0 for R> a. (8%)arrow_forwardIn free space, a linear charge density > is on the z axis. Get the electric force over a unit charge "q" located at P (1, 2, 3) m if the linear charge density is in -4 m < z < 4m = 2μC m Give the answer in unit vectors terms.arrow_forward(b) It was measured that the electric field at point P with magnitude 450 N/C just outside the outer surface of a hollow spherical conductor. The direction of the electric field is directed outward. The hollow spherical conductor has an inner radius of 15 cm and outer radius of 30 cm. After that, another particle with unknown charge Q is put at the center of the sphere, the electric field at point P is still directed outward but the magnitude of the electric field decreased down to 180 N/C. i. Calculate the net charge enclosed by the outer surface before particle Q was introduced ii. Calculate charge Q After charge Q was introduced, iii. Determine the charge on the inner surface of the conductor iv. Determine the charge on the outer surface of the conductorarrow_forward..33 O In Fig. 22-56, a "semi- infinite" nonconducting rod (that is, infinite in one direction only) has uniform linear charge density A. Show that the electric field E, at point P makes an angle of 45° with the rod and that this result is independent of the distance R. (Hint: Separately find the component of E, parallel to the rod and the component perpendicular to the rod.) Figure 22-56 Problem 33.arrow_forward2. -- -) An infinite, insulating cylinder of radius r, is surrounded by an air gap and a thin, cylindrical conducting shell of radius ry. The insulating cylinder carries constant volume charge density p and the conducting shell carries a constant area charge density o. (a) ) Use Gauss's law to calculate the quantity f EedA for the Gaussian shape most appropriate for this problem. (b) | Find the electric field in the regionr < rı (inside the volume charge distribution). (c) ) Find the electric field in the region rarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_iosRecommended textbooks for you
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