Organic Chemistry, Binder Ready Version
Organic Chemistry, Binder Ready Version
2nd Edition
ISBN: 9781118454312
Author: David R. Klein
Publisher: WILEY
Question
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Chapter 23, Problem 71PP

(a)

Interpretation Introduction

Interpretation: The products of the reactions in which diazonium salt is treated with the given reagents have to be drawn.

Concept Introduction:

A compound containing an amino group is treated with sodium nitrite and HCl leading to the formation of diazonium salt.

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  1

Sandmeyer reactions use copper salts as the reagents.  Here, aryldiazonium salt is converted into aryl halides or aryl cyanides by using copper halides or copper cyanides.

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  2

Schiemann reaction is the reaction in which diazonium salt is converted into fluoro group using fluoroboric acid (HBF4).

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  3

To find: Get the product of the reaction in which diazonium salt is treated with the given reagent (a)

Put the reaction of m-bromoaniline with NaNO2 and HCl

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  4

(b)

Interpretation Introduction

Interpretation: The products of the reactions in which diazonium salt is treated with the given reagents have to be drawn.

Concept Introduction:

A compound containing an amino group is treated with sodium nitrite and HCl leading to the formation of diazonium salt.

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  5

Sandmeyer reactions use copper salts as the reagents.  Here, aryldiazonium salt is converted into aryl halides or aryl cyanides by using copper halides or copper cyanides.

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  6

Schiemann reaction is the reaction in which diazonium salt is converted into fluoro group using fluoroboric acid (HBF4).

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  7

To find: Get the product of the reaction in which diazonium salt is treated with the given reagent (b)

Put the reaction of m-bromoaniline with NaNO2 and HCl

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  8

(c)

Interpretation Introduction

Interpretation: The products of the reactions in which diazonium salt is treated with the given reagents have to be drawn.

Concept Introduction:

A compound containing an amino group is treated with sodium nitrite and HCl leading to the formation of diazonium salt.

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  9

Sandmeyer reactions use copper salts as the reagents.  Here, aryldiazonium salt is converted into aryl halides or aryl cyanides by using copper halides or copper cyanides.

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  10

Schiemann reaction is the reaction in which diazonium salt is converted into fluoro group using fluoroboric acid (HBF4).

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  11

To find: Get the product of the reaction in which diazonium salt is treated with the given reagent

Put the reaction of m-bromoaniline with NaNO2 and HCl

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  12

(d)

Interpretation Introduction

Interpretation: The products of the reactions in which diazonium salt is treated with the given reagents have to be drawn.

Concept Introduction:

A compound containing an amino group is treated with sodium nitrite and HCl leading to the formation of diazonium salt.

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  13

Sandmeyer reactions use copper salts as the reagents.  Here, aryldiazonium salt is converted into aryl halides or aryl cyanides by using copper halides or copper cyanides.

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  14

Schiemann reaction is the reaction in which diazonium salt is converted into fluoro group using fluoroboric acid (HBF4).

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  15

To find: Get the product of the reaction in which diazonium salt is treated with the given reagent

Put the reaction of m-bromoaniline with NaNO2 and HCl

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  16

(e)

Interpretation Introduction

Interpretation: The products of the reactions in which diazonium salt is treated with the given reagents have to be drawn.

Concept Introduction:

A compound containing an amino group is treated with sodium nitrite and HCl leading to the formation of diazonium salt.

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  17

Sandmeyer reactions use copper salts as the reagents.  Here, aryldiazonium salt is converted into aryl halides or aryl cyanides by using copper halides or copper cyanides.

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  18

Schiemann reaction is the reaction in which diazonium salt is converted into fluoro group using fluoroboric acid (HBF4).

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  19

To find: Get the product of the reaction in which diazonium salt is treated with the given reagent (e)

Put the reaction of m-bromoaniline with NaNO2 and HCl

Organic Chemistry, Binder Ready Version, Chapter 23, Problem 71PP , additional homework tip  20

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Chapter 23 Solutions

Organic Chemistry, Binder Ready Version

Ch. 23.4 - Prob. 10CCCh. 23.4 - Prob. 11CCCh. 23.5 - Prob. 2LTSCh. 23.5 - Prob. 12PTSCh. 23.5 - Prob. 13PTSCh. 23.6 - Prob. 3LTSCh. 23.6 - Prob. 14PTSCh. 23.6 - Prob. 15ATSCh. 23.6 - Prob. 16ATSCh. 23.6 - Prob. 17ATSCh. 23.7 - Prob. 18PTSCh. 23.7 - Prob. 19PTSCh. 23.7 - Prob. 20PTSCh. 23.7 - Prob. 21ATSCh. 23.8 - Prob. 22CCCh. 23.8 - Prob. 23CCCh. 23.8 - Prob. 24CCCh. 23.9 - Prob. 5LTSCh. 23.9 - Prob. 25PTSCh. 23.9 - Prob. 26ATSCh. 23.9 - Prob. 27ATSCh. 23.9 - Prob. 28ATSCh. 23.10 - Prob. 29CCCh. 23.11 - Prob. 30CCCh. 23.11 - Prob. 6LTSCh. 23.11 - Prob. 31PTSCh. 23.11 - Prob. 32ATSCh. 23.11 - Prob. 33ATSCh. 23.12 - Prob. 34CCCh. 23.12 - Prob. 35CCCh. 23.13 - Prob. 36CCCh. 23.13 - Prob. 37CCCh. 23 - Prob. 38PPCh. 23 - Prob. 39PPCh. 23 - Prob. 40PPCh. 23 - Prob. 41PPCh. 23 - Prob. 42PPCh. 23 - Prob. 43PPCh. 23 - Prob. 44PPCh. 23 - Prob. 45PPCh. 23 - Prob. 46PPCh. 23 - Prob. 47PPCh. 23 - Prob. 48PPCh. 23 - Prob. 49PPCh. 23 - Prob. 50PPCh. 23 - Prob. 51PPCh. 23 - Prob. 52PPCh. 23 - Prob. 53PPCh. 23 - Prob. 54PPCh. 23 - Prob. 55PPCh. 23 - Prob. 56PPCh. 23 - Prob. 57PPCh. 23 - Prob. 58PPCh. 23 - Prob. 59PPCh. 23 - Prob. 60PPCh. 23 - Prob. 61PPCh. 23 - Prob. 62PPCh. 23 - Prob. 63PPCh. 23 - Prob. 64PPCh. 23 - Prob. 65PPCh. 23 - Prob. 66PPCh. 23 - Prob. 67PPCh. 23 - Prob. 68PPCh. 23 - Prob. 69PPCh. 23 - Prob. 70PPCh. 23 - Prob. 71PPCh. 23 - Prob. 72PPCh. 23 - Prob. 73PPCh. 23 - Prob. 74PPCh. 23 - Prob. 75PPCh. 23 - Prob. 76PPCh. 23 - Prob. 77IPCh. 23 - Prob. 78IPCh. 23 - Prob. 79IPCh. 23 - Prob. 80IPCh. 23 - Prob. 81IPCh. 23 - Prob. 82IPCh. 23 - Prob. 83IPCh. 23 - Prob. 84IPCh. 23 - Prob. 85IPCh. 23 - Prob. 86IPCh. 23 - Prob. 87IPCh. 23 - Prob. 88IPCh. 23 - Prob. 89IPCh. 23 - Prob. 90IPCh. 23 - Prob. 91CPCh. 23 - Prob. 92CPCh. 23 - Prob. 93CPCh. 23 - Prob. 94CPCh. 23 - Prob. 95CPCh. 23 - Prob. 96CPCh. 23 - Prob. 97CPCh. 23 - Prob. 98CP
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