The major product of methadone has to be found via Hofmann elimination Concept Introduction : The reagents such as methyl iodide and silver oxide are given and used as the reaction conditions in the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternary ammonium salt which is a excellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes . Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene. To find: The major product of methadone via Hofmann elimination Draw and analyze the structure of methadone

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Answer 1

Question

Chapter 23, Problem 57PP

Interpretation Introduction

Interpretation: The major product of methadone has to be found via Hofmann elimination

Concept Introduction:

The reagents such as methyl iodide and silver oxide are given and used as the reaction conditions in the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternary ammonium salt which is a excellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes. Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

To find: The major product of methadone via Hofmann elimination

Draw and analyze the structure of methadone

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Answer 2

Question

Chapter 23, Problem 57PP

Interpretation Introduction

Interpretation: The major product of methadone has to be found via Hofmann elimination

Concept Introduction:

The reagents such as methyl iodide and silver oxide are given and used as the reaction conditions in the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternary ammonium salt which is a excellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes. Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

To find: The major product of methadone via Hofmann elimination

Draw and analyze the structure of methadone

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 23, Problem 57PP

Interpretation Introduction

Interpretation: The major product of methadone has to be found via Hofmann elimination

Concept Introduction:

The reagents such as methyl iodide and silver oxide are given and used as the reaction conditions in the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternary ammonium salt which is a excellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes. Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

To find: The major product of methadone via Hofmann elimination

Draw and analyze the structure of methadone

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 23, Problem 57PP

Interpretation Introduction

Interpretation: The major product of methadone has to be found via Hofmann elimination

Concept Introduction:

The reagents such as methyl iodide and silver oxide are given and used as the reaction conditions in the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternary ammonium salt which is a excellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes. Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

To find: The major product of methadone via Hofmann elimination

Draw and analyze the structure of methadone

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 23, Problem 57PP

Interpretation Introduction

Interpretation: The major product of methadone has to be found via Hofmann elimination

Concept Introduction:

The reagents such as methyl iodide and silver oxide are given and used as the reaction conditions in the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternary ammonium salt which is a excellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes. Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

To find: The major product of methadone via Hofmann elimination

Draw and analyze the structure of methadone

Answer 6

Chapter 23, Problem 57PP

Interpretation Introduction

Interpretation: The major product of methadone has to be found via Hofmann elimination

Concept Introduction:

The reagents such as methyl iodide and silver oxide are given and used as the reaction conditions in the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternary ammonium salt which is a excellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes. Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

To find: The major product of methadone via Hofmann elimination

Draw and analyze the structure of methadone

Answer 7

Chapter 23, Problem 57PP

Interpretation Introduction

Interpretation: The major product of methadone has to be found via Hofmann elimination

Concept Introduction:

The reagents such as methyl iodide and silver oxide are given and used as the reaction conditions in the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternary ammonium salt which is a excellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes. Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

To find: The major product of methadone via Hofmann elimination

Draw and analyze the structure of methadone

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 23.2 - Prob. 1LTS Ch. 23.2 - Prob. 1PTS Ch. 23.2 - Prob. 2ATS Ch. 23.2 - Prob. 3ATS Ch. 23.3 - Prob. 4CC Ch. 23.3 - Prob. 5CC Ch. 23.3 - Prob. 6CC Ch. 23.3 - Prob. 7CC Ch. 23.3 - Prob. 8CC Ch. 23.3 - Prob. 9CC

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Chapter 23 Solutions