The structure, name and the class belongs for the product fromed from the reaction between butanoic acid and methylamine should be given. The balanced chemical equation for the reaction of butanoic acid andmethylamine should be written. Concept introduction: Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia. Here, the − O H group is attached to the carbonyl carbon atom of the carboxylic acid is being replaced by − N H 2 , − N H R ' or − N R ' 2 group in the an amine or ammonia forming amide and water. Chemical equation is the representation of a chemical reaction , in which the reactants and products of the reactions are represented left and right side of an arrow respectively by using their respective chemical formulas. Balanced chemical equation of a reaction is written according to law of conservation of mass.

Question

Calculate Ecell at 25.0 oC using the following half-reactions with [Ag+1] = 0.0100 M and [Sn+2] = 0.0200 M. Ag+1(aq) + 1e-1 Ag(s) Sn+2(aq) + 2e-1 Sn(s)

Answer 1

Question

Chapter 23, Problem 67PS

Interpretation Introduction

Interpretation: The structure, name and the class belongs for the product fromed from the reaction between butanoic acid and methylamine should be given. The balanced chemical equation for the reaction of butanoic acid andmethylamine should be written.

Concept introduction:

Amide Formation: Amide is formed when a carboxylic acid reacts with an amine or ammonia.

Here, the −OH group is attached to the carbonyl carbon atom of the carboxylic acid is being replaced by −NH2, −NHR' or −NR'2 group in the an amine or ammonia forming amide and water.

Chemical equation is the representation of a chemical reaction, in which the reactants and products of the reactions are represented left and right side of an arrow respectively by using their respective chemical formulas.

Balanced chemical equation of a reaction is written according to law of conservation of mass.

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Calculate Ecell at 25.0 oC using the following half-reactions with [Ag+1] = 0.0100 M and [Sn+2] = 0.0200 M. Ag+1(aq) + 1e-1 Ag(s) Sn+2(aq) + 2e-1 Sn(s)

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