To identify the carbonyl compound having molecular formula C 3 H 6 O . To draw the structures of two possible carbonyl compounds. Concept introduction: The hydrocarbons which have general formula C n H 2n O are come in the catagory of carbonyl compounds. The carbonyl compounds have R 2 CO and RCHO functional groups. So, carbonyl compounds are of two types (1) Aldehydes ( RCHO ) (2) Ketones ( R 2 CO ) . These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is -al , while for ketone -one . For example, propanal is an aldehyde and propanone is a ketone. The reaction of an aldehyde with KMnO 4 gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so KMnO 4 is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

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Answer 1

Question

Chapter 23, Problem 107IL

(a)

Interpretation Introduction

Interpretation:

To identify the carbonyl compound having molecular formula $C3H6O$ . To draw the structures of two possible carbonyl compounds.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

(b)

Interpretation Introduction

Interpretation:

To identify the carbonyl compound having molecular formula $C3H6O$ . To decide which of the structure is correct.

(c) To write the name of product obtained after oxidation.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

(c)

Interpretation Introduction

Interpretation:

To write the name of product obtained after oxidation.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

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Answer 2

Question

Chapter 23, Problem 107IL

(a)

Interpretation Introduction

Interpretation:

To identify the carbonyl compound having molecular formula $C3H6O$ . To draw the structures of two possible carbonyl compounds.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

(b)

Interpretation Introduction

Interpretation:

To identify the carbonyl compound having molecular formula $C3H6O$ . To decide which of the structure is correct.

(c) To write the name of product obtained after oxidation.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

(c)

Interpretation Introduction

Interpretation:

To write the name of product obtained after oxidation.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

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Answer 3

Question

Chapter 23, Problem 107IL

(a)

Interpretation Introduction

Interpretation:

To identify the carbonyl compound having molecular formula $C3H6O$ . To draw the structures of two possible carbonyl compounds.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

(b)

Interpretation Introduction

Interpretation:

To identify the carbonyl compound having molecular formula $C3H6O$ . To decide which of the structure is correct.

(c) To write the name of product obtained after oxidation.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

(c)

Interpretation Introduction

Interpretation:

To write the name of product obtained after oxidation.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

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Answer 4

Question

Chapter 23, Problem 107IL

(a)

Interpretation Introduction

Interpretation:

To identify the carbonyl compound having molecular formula $C3H6O$ . To draw the structures of two possible carbonyl compounds.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

(b)

Interpretation Introduction

Interpretation:

To identify the carbonyl compound having molecular formula $C3H6O$ . To decide which of the structure is correct.

(c) To write the name of product obtained after oxidation.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

(c)

Interpretation Introduction

Interpretation:

To write the name of product obtained after oxidation.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

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Answer 5

Chapter 23, Problem 107IL

(a)

Interpretation Introduction

Interpretation:

To identify the carbonyl compound having molecular formula $C3H6O$ . To draw the structures of two possible carbonyl compounds.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

(b)

Interpretation Introduction

Interpretation:

To identify the carbonyl compound having molecular formula $C3H6O$ . To decide which of the structure is correct.

(c) To write the name of product obtained after oxidation.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

(c)

Interpretation Introduction

Interpretation:

To write the name of product obtained after oxidation.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

Answer 6

Chapter 23, Problem 107IL

(a)

Interpretation Introduction

Interpretation:

To identify the carbonyl compound having molecular formula $C3H6O$ . To draw the structures of two possible carbonyl compounds.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

Answer 7

Chapter 23, Problem 107IL

(a)

Interpretation Introduction

Interpretation:

To identify the carbonyl compound having molecular formula $C3H6O$ . To draw the structures of two possible carbonyl compounds.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

Answer 8

(b)

Interpretation Introduction

Interpretation:

To identify the carbonyl compound having molecular formula $C3H6O$ . To decide which of the structure is correct.

(c) To write the name of product obtained after oxidation.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

Answer 9

(b)

Interpretation Introduction

Interpretation:

To identify the carbonyl compound having molecular formula $C3H6O$ . To decide which of the structure is correct.

(c) To write the name of product obtained after oxidation.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

Answer 10

(c)

Interpretation Introduction

Interpretation:

To write the name of product obtained after oxidation.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

Answer 11

(c)

Interpretation Introduction

Interpretation:

To write the name of product obtained after oxidation.

Concept introduction:

The hydrocarbons which have general formula $CnH2nO$ are come in the catagory of carbonyl compounds. The carbonyl compounds have $R2CO$ and $RCHO$ functional groups. So, carbonyl compounds are of two types (1) Aldehydes $(RCHO)$ (2) Ketones $(R2CO)$ .

These compounds have same molecular formula but different structural formula. Therfore their systematic names are different. For aldehydes the suffix written in the end of parent carbon chain is $-al$ , while for ketone $-one$ . For example, $propanal$ is an aldehyde and $propanone$ is a ketone.

The reaction of an aldehyde with $KMnO4$ gives a carboxylic acid. The conversion of an aldehyde to a carboxylic acid is an oxidation reaction, so $KMnO4$ is acting as a oxidizing agent. However, a ketone does not undergo oxidation in the presence of oxidizing agent.

Answer 12

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Answer 23

Ch. 23.2 - (a) Draw the nine isomers having the formula...Ch. 23.2 - Prob. 23.2CYU Ch. 23.2 - There are 17 possible alkene isomers with the...Ch. 23.2 - Prob. 23.4CYU Ch. 23.2 - Aniline, C6H5NH2, is the common name for...Ch. 23.3 - Draw the structure of 1-butanol and alcohols that...Ch. 23.4 - (a) Name each of the following compounds and its...Ch. 23.5 - Kevlar is a well-known polymer that is now used to...Ch. 23.5 - Prob. 1.1ACP Ch. 23.5 - Prob. 1.2ACP

Solution Summary: The author explains the structure of two possible carbonyl compounds.

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