(a) Interpretation: The compound 2, 2-dimethyl-1-propanamine and 2-methyl-2-butanamine is to be distinguished on the basis of C 13 NMR spectroscopy. Concept introduction: In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Question

Want to see the full answer?

Answer 1

Question

Chapter 23, Problem 23.6P

Interpretation Introduction

(a)

Interpretation:

The compound 2, 2-dimethyl-1-propanamine and 2-methyl-2-butanamine is to be distinguished on the basis of C13 NMR spectroscopy.

Concept introduction:

In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Interpretation Introduction

(b)

Interpretation:

The compound trans-1, 2-cyclohexanediamine and trans-1, 4-cyclohexanediamine is to be distinguished on the basis of C13 NMR spectroscopy.

Concept introduction:

In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

8) CH3 CH3 O 36 Hu H CH3 CH3 Fo H H Answer the following questions, which refer to the two acetonide diastereomers shown above. a) Would you expect any difference in the number of peaks in the ¹H NMR spectra of each acetonide? (Y or N). b) Would you expect any difference in the number of peaks in the 13C NMR spectra of each acetonide? (Y or N) c) Would you expect any difference in the integral values for the peaks in the ¹H NMR spectra of each acetonide? (Y or N) d) Would you expect any difference in the multiplicities for the peaks in the ¹H NMR spectra of each acetonide? (Y or N). e) Would you expect any difference in the chemical shifts for the peaks in the ¹H NMR spectra of each acetonide? (Y or N)

Compound X (molecular formula C10H12O) was treated with NH2NH2, −OH to yield compound Y (molecular formula C10H14). Based on the 1HNMR spectra of X and Y given below, what are the structures of X and Y?

A compound with a molecular formula C9H120 has the H NMR spectrum shown. Which of the following structures is consistent with this spectrum? 2 1 exchanges with D20 PPM HO HO III ÓH IV V O II O IV

Answer 2

Question

Chapter 23, Problem 23.6P

Interpretation Introduction

(a)

Interpretation:

The compound 2, 2-dimethyl-1-propanamine and 2-methyl-2-butanamine is to be distinguished on the basis of C13 NMR spectroscopy.

Concept introduction:

In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Interpretation Introduction

(b)

Interpretation:

The compound trans-1, 2-cyclohexanediamine and trans-1, 4-cyclohexanediamine is to be distinguished on the basis of C13 NMR spectroscopy.

Concept introduction:

In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 23, Problem 23.6P

Interpretation Introduction

(a)

Interpretation:

The compound 2, 2-dimethyl-1-propanamine and 2-methyl-2-butanamine is to be distinguished on the basis of C13 NMR spectroscopy.

Concept introduction:

In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Interpretation Introduction

(b)

Interpretation:

The compound trans-1, 2-cyclohexanediamine and trans-1, 4-cyclohexanediamine is to be distinguished on the basis of C13 NMR spectroscopy.

Concept introduction:

In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 23, Problem 23.6P

Interpretation Introduction

(a)

Interpretation:

The compound 2, 2-dimethyl-1-propanamine and 2-methyl-2-butanamine is to be distinguished on the basis of C13 NMR spectroscopy.

Concept introduction:

In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Interpretation Introduction

(b)

Interpretation:

The compound trans-1, 2-cyclohexanediamine and trans-1, 4-cyclohexanediamine is to be distinguished on the basis of C13 NMR spectroscopy.

Concept introduction:

In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 23, Problem 23.6P

Interpretation Introduction

(a)

Interpretation:

The compound 2, 2-dimethyl-1-propanamine and 2-methyl-2-butanamine is to be distinguished on the basis of C13 NMR spectroscopy.

Concept introduction:

In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Interpretation Introduction

(b)

Interpretation:

The compound trans-1, 2-cyclohexanediamine and trans-1, 4-cyclohexanediamine is to be distinguished on the basis of C13 NMR spectroscopy.

Concept introduction:

In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Answer 6

Chapter 23, Problem 23.6P

Interpretation Introduction

(a)

Interpretation:

The compound 2, 2-dimethyl-1-propanamine and 2-methyl-2-butanamine is to be distinguished on the basis of C13 NMR spectroscopy.

Concept introduction:

In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Answer 7

Chapter 23, Problem 23.6P

Interpretation Introduction

(a)

Interpretation:

The compound 2, 2-dimethyl-1-propanamine and 2-methyl-2-butanamine is to be distinguished on the basis of C13 NMR spectroscopy.

Concept introduction:

In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The compound trans-1, 2-cyclohexanediamine and trans-1, 4-cyclohexanediamine is to be distinguished on the basis of C13 NMR spectroscopy.

Concept introduction:

In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The compound trans-1, 2-cyclohexanediamine and trans-1, 4-cyclohexanediamine is to be distinguished on the basis of C13 NMR spectroscopy.

Concept introduction:

In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. The chemical shift value depended upon its surrounded protons.

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 23 - Prob. 23.1P Ch. 23 - Prob. 23.2P Ch. 23 - Prob. 23.3P Ch. 23 - Prob. 23.4P Ch. 23 - Prob. 23.5P Ch. 23 - Prob. 23.6P Ch. 23 - Prob. 23.7P Ch. 23 - Prob. 23.8P Ch. 23 - Prob. 23.9P Ch. 23 - Prob. 23.10P

Solution Summary: The author explains the difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus.

Concept explainers

Videos

Want to see the full answer?

Chapter 23 Solutions