(a) Interpretation: The amines A at base peak m / z = 72 and B at base peak m / z = 58 are to be identified among: 2-methyl-2-heptanamine , and N-ethyl-4-methyl-2-pentanamine on the basis of their mass spectrum. Concept introduction: Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as ( M + 1 ) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

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Answer 1

Question

Chapter 23, Problem 23.67AP

Interpretation Introduction

(a)

Interpretation:

The amines A at base peak m/z=72 and B at base peak m/z=58 are to be identified among: 2-methyl-2-heptanamine, and N-ethyl-4-methyl-2-pentanamine on the basis of their mass spectrum.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Interpretation Introduction

(b)

Interpretation:

The m/z value of the peak resulted from the α- cleavage of tributylamine is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

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1. Calculate the accurate monoisotopic mass (using all 1H, 12C, 14N, 160 and 35CI) for your product using the table in your lab manual. Don't include the Cl, since you should only have [M+H]*. Compare this to the value you see on the LC-MS printout. How much different are they? 2. There are four isotopic peaks for the [M+H]* ion at m/z 240, 241, 242 and 243. For one point of extra credit, explain what each of these is and why they are present. 3. There is a fragment ion at m/z 184. For one point of extra credit, identify this fragment and confirm by calculating the accurate monoisotopic mass. 4. The UV spectrum is also at the bottom of your printout. For one point of extra credit, look up the UV spectrum of bupropion on Google Images and compare to your spectrum. Do they match? Cite your source. 5. For most of you, there will be a second chromatographic peak whose m/z is 74 (to a round number). For one point of extra credit, see if you can identify this molecule as well and confirm by…

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Answer 2

Question

Chapter 23, Problem 23.67AP

Interpretation Introduction

(a)

Interpretation:

The amines A at base peak m/z=72 and B at base peak m/z=58 are to be identified among: 2-methyl-2-heptanamine, and N-ethyl-4-methyl-2-pentanamine on the basis of their mass spectrum.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Interpretation Introduction

(b)

Interpretation:

The m/z value of the peak resulted from the α- cleavage of tributylamine is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

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Answer 3

Question

Chapter 23, Problem 23.67AP

Interpretation Introduction

(a)

Interpretation:

The amines A at base peak m/z=72 and B at base peak m/z=58 are to be identified among: 2-methyl-2-heptanamine, and N-ethyl-4-methyl-2-pentanamine on the basis of their mass spectrum.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Interpretation Introduction

(b)

Interpretation:

The m/z value of the peak resulted from the α- cleavage of tributylamine is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Expert Solution & Answer

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Answer 4

Question

Chapter 23, Problem 23.67AP

Interpretation Introduction

(a)

Interpretation:

The amines A at base peak m/z=72 and B at base peak m/z=58 are to be identified among: 2-methyl-2-heptanamine, and N-ethyl-4-methyl-2-pentanamine on the basis of their mass spectrum.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Interpretation Introduction

(b)

Interpretation:

The m/z value of the peak resulted from the α- cleavage of tributylamine is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

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Answer 5

Chapter 23, Problem 23.67AP

Interpretation Introduction

(a)

Interpretation:

The amines A at base peak m/z=72 and B at base peak m/z=58 are to be identified among: 2-methyl-2-heptanamine, and N-ethyl-4-methyl-2-pentanamine on the basis of their mass spectrum.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Interpretation Introduction

(b)

Interpretation:

The m/z value of the peak resulted from the α- cleavage of tributylamine is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Answer 6

Chapter 23, Problem 23.67AP

Interpretation Introduction

(a)

Interpretation:

The amines A at base peak m/z=72 and B at base peak m/z=58 are to be identified among: 2-methyl-2-heptanamine, and N-ethyl-4-methyl-2-pentanamine on the basis of their mass spectrum.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Answer 7

Chapter 23, Problem 23.67AP

Interpretation Introduction

(a)

Interpretation:

The amines A at base peak m/z=72 and B at base peak m/z=58 are to be identified among: 2-methyl-2-heptanamine, and N-ethyl-4-methyl-2-pentanamine on the basis of their mass spectrum.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The m/z value of the peak resulted from the α- cleavage of tributylamine is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The m/z value of the peak resulted from the α- cleavage of tributylamine is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 23 - Prob. 23.1P Ch. 23 - Prob. 23.2P Ch. 23 - Prob. 23.3P Ch. 23 - Prob. 23.4P Ch. 23 - Prob. 23.5P Ch. 23 - Prob. 23.6P Ch. 23 - Prob. 23.7P Ch. 23 - Prob. 23.8P Ch. 23 - Prob. 23.9P Ch. 23 - Prob. 23.10P

Solution Summary: The author explains that the amines A at base peak m/z=72 and B are identified on the basis of their mass spectrum.

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