(a) Interpretation: Whether the reaction between ammonia and bromobenzene on heating is expected to form tetraphenylammonium bromide or not is to be stated. Concept introduction: Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π -electrons.

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Answer 1

Question

Chapter 23, Problem 23.20P

Interpretation Introduction

(a)

Interpretation:

Whether the reaction between ammonia and bromobenzene on heating is expected to form tetraphenylammonium bromide or not is to be stated.

Concept introduction:

Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π-electrons.

Interpretation Introduction

(b)

Interpretation:

The catalyst used to bring about the given reaction under relatively mild conditions is to be predicted.

Concept introduction:

Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π-electrons.

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PLEASE READ!!! I DONT WANT EXAMPLES, I DONT WANT WORDS OR PARAGRAPHS FOR THE MECHANISM!!! THANKS First image: QUESTION 6. I have to show, with ARROWS and STRUCTURES, the mechanism of the reaction at the bottom. Also I have to show by mecanism why the reaction wouldn't work if the alcohol was primary. I also tried to draw the mechanism, tell me what to change. Please note that its an AMIDE thats formed not an AMINE the nitrogen has ONE hydrogen and one Phenyl-C-Phenyl. I already asked for this mechanism and got as a final product ...-NH2 not whats shown on the picture, thank you Ths second part. QUESTION 3. I just need a way to synthesize the lactone A, I already started please continue from where I left it Second image: I simply need the products, substrates or reagents, thank you

Indicate how to prepare a 10% sodium hydroxide (NaOH) solution to a slightly alkaline pH.

Answer 2

Question

Chapter 23, Problem 23.20P

Interpretation Introduction

(a)

Interpretation:

Whether the reaction between ammonia and bromobenzene on heating is expected to form tetraphenylammonium bromide or not is to be stated.

Concept introduction:

Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π-electrons.

Interpretation Introduction

(b)

Interpretation:

The catalyst used to bring about the given reaction under relatively mild conditions is to be predicted.

Concept introduction:

Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π-electrons.

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Answer 3

Question

Chapter 23, Problem 23.20P

Interpretation Introduction

(a)

Interpretation:

Whether the reaction between ammonia and bromobenzene on heating is expected to form tetraphenylammonium bromide or not is to be stated.

Concept introduction:

Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π-electrons.

Interpretation Introduction

(b)

Interpretation:

The catalyst used to bring about the given reaction under relatively mild conditions is to be predicted.

Concept introduction:

Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π-electrons.

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Answer 4

Question

Chapter 23, Problem 23.20P

Interpretation Introduction

(a)

Interpretation:

Whether the reaction between ammonia and bromobenzene on heating is expected to form tetraphenylammonium bromide or not is to be stated.

Concept introduction:

Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π-electrons.

Interpretation Introduction

(b)

Interpretation:

The catalyst used to bring about the given reaction under relatively mild conditions is to be predicted.

Concept introduction:

Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π-electrons.

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Answer 5

Chapter 23, Problem 23.20P

Interpretation Introduction

(a)

Interpretation:

Whether the reaction between ammonia and bromobenzene on heating is expected to form tetraphenylammonium bromide or not is to be stated.

Concept introduction:

Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π-electrons.

Interpretation Introduction

(b)

Interpretation:

The catalyst used to bring about the given reaction under relatively mild conditions is to be predicted.

Concept introduction:

Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π-electrons.

Answer 6

Chapter 23, Problem 23.20P

Interpretation Introduction

(a)

Interpretation:

Whether the reaction between ammonia and bromobenzene on heating is expected to form tetraphenylammonium bromide or not is to be stated.

Concept introduction:

Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π-electrons.

Answer 7

Chapter 23, Problem 23.20P

Interpretation Introduction

(a)

Interpretation:

Whether the reaction between ammonia and bromobenzene on heating is expected to form tetraphenylammonium bromide or not is to be stated.

Concept introduction:

Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π-electrons.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The catalyst used to bring about the given reaction under relatively mild conditions is to be predicted.

Concept introduction:

Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π-electrons.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The catalyst used to bring about the given reaction under relatively mild conditions is to be predicted.

Concept introduction:

Ammonia acts as a base as well as a nucleophile. Bromobenzene is electron-rich species due to bromine which act as an electron-donating group. Resonance stabilizes the phenyl ring by making it electron efficient with delocalization of π-electrons.

Answer 10

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Answer 13

Ch. 23 - Prob. 23.1P Ch. 23 - Prob. 23.2P Ch. 23 - Prob. 23.3P Ch. 23 - Prob. 23.4P Ch. 23 - Prob. 23.5P Ch. 23 - Prob. 23.6P Ch. 23 - Prob. 23.7P Ch. 23 - Prob. 23.8P Ch. 23 - Prob. 23.9P Ch. 23 - Prob. 23.10P

Solution Summary: The author explains that the reaction between ammonia and bromobenzene on heating is expected to form tetraphenylammonium bromide.

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Chapter 23 Solutions