(a) Interpretation: The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined. Concept introduction: Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding. When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides. All the oxygen in oxides are in − 2 oxidation state.

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Answer 1

Question

Chapter 22, Problem 22.25CP

Interpretation Introduction

(a)

Interpretation:

The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

All the oxygen in oxides are in −2 oxidation state.

Interpretation Introduction

(b)

Interpretation:

Each oxide should be identified as molecular or a solid with an infinity extended three-dimensional structure

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Interpretation Introduction

(c)

Interpretation:

The oxides which are likely to be a gas or a liquid and which are likely to be a high-melting solid should be determined.

Concept introduction:

Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.

Interpretation Introduction

(d)

Interpretation:

The identity of the other element in (2) and (3) should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

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Identify the missing starting materials/ reagents/ products in the following reactions. Show the stereochemistry clearly in the structures, if any. If there is a major product, draw the structures of the major product with stereochemistry clearly indicated where applicable. Show only the diastereomers (you do not have to draw the pairs of enantiomers). If you believe that multiple products are formed in approximately equal amounts (hence neither is the major product), draw the structures of the products, and show the detailed mechanism of these reactions to justify the formation of the multiple products. If you believe no product is formed, explain why briefly. (6 mark for each, except f and g, which are 10 mark each)

3. What starting material would you use to synthesize 3-hydroxypentanoic acid using a NaBH4 reduction?

1. Give stereochemical (Fischer projection) formulas for all (but no extras) the stereoisomers that could theoretically form during the reduction of a. the carbonyl group of 2-methyl-3--pentanone b. both carbonyl groups of 2,4-pentanedione (careful!) 2. Predict the products of the reduction of O=CCH2CH2CH2C=O with a. LiAlH4 b. NaBH4 CH3 OH

Answer 2

Question

Chapter 22, Problem 22.25CP

Interpretation Introduction

(a)

Interpretation:

The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

All the oxygen in oxides are in −2 oxidation state.

Interpretation Introduction

(b)

Interpretation:

Each oxide should be identified as molecular or a solid with an infinity extended three-dimensional structure

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Interpretation Introduction

(c)

Interpretation:

The oxides which are likely to be a gas or a liquid and which are likely to be a high-melting solid should be determined.

Concept introduction:

Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.

Interpretation Introduction

(d)

Interpretation:

The identity of the other element in (2) and (3) should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

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Answer 3

Question

Chapter 22, Problem 22.25CP

Interpretation Introduction

(a)

Interpretation:

The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

All the oxygen in oxides are in −2 oxidation state.

Interpretation Introduction

(b)

Interpretation:

Each oxide should be identified as molecular or a solid with an infinity extended three-dimensional structure

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Interpretation Introduction

(c)

Interpretation:

The oxides which are likely to be a gas or a liquid and which are likely to be a high-melting solid should be determined.

Concept introduction:

Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.

Interpretation Introduction

(d)

Interpretation:

The identity of the other element in (2) and (3) should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

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Answer 4

Question

Chapter 22, Problem 22.25CP

Interpretation Introduction

(a)

Interpretation:

The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

All the oxygen in oxides are in −2 oxidation state.

Interpretation Introduction

(b)

Interpretation:

Each oxide should be identified as molecular or a solid with an infinity extended three-dimensional structure

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Interpretation Introduction

(c)

Interpretation:

The oxides which are likely to be a gas or a liquid and which are likely to be a high-melting solid should be determined.

Concept introduction:

Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.

Interpretation Introduction

(d)

Interpretation:

The identity of the other element in (2) and (3) should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

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Answer 5

Chapter 22, Problem 22.25CP

Interpretation Introduction

(a)

Interpretation:

The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

All the oxygen in oxides are in −2 oxidation state.

Interpretation Introduction

(b)

Interpretation:

Each oxide should be identified as molecular or a solid with an infinity extended three-dimensional structure

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Interpretation Introduction

(c)

Interpretation:

The oxides which are likely to be a gas or a liquid and which are likely to be a high-melting solid should be determined.

Concept introduction:

Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.

Interpretation Introduction

(d)

Interpretation:

The identity of the other element in (2) and (3) should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Answer 6

Chapter 22, Problem 22.25CP

Interpretation Introduction

(a)

Interpretation:

The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

All the oxygen in oxides are in −2 oxidation state.

Answer 7

Chapter 22, Problem 22.25CP

Interpretation Introduction

(a)

Interpretation:

The oxidation state of oxygen in each oxide and the oxidation state of the other element should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

All the oxygen in oxides are in −2 oxidation state.

Answer 8

Interpretation Introduction

(b)

Interpretation:

Each oxide should be identified as molecular or a solid with an infinity extended three-dimensional structure

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Answer 9

Interpretation Introduction

(b)

Interpretation:

Each oxide should be identified as molecular or a solid with an infinity extended three-dimensional structure

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The oxides which are likely to be a gas or a liquid and which are likely to be a high-melting solid should be determined.

Concept introduction:

Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The oxides which are likely to be a gas or a liquid and which are likely to be a high-melting solid should be determined.

Concept introduction:

Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.

Answer 12

Interpretation Introduction

(d)

Interpretation:

The identity of the other element in (2) and (3) should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Answer 13

Interpretation Introduction

(d)

Interpretation:

The identity of the other element in (2) and (3) should be determined.

Concept introduction:

Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.

When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.

Answer 14

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Answer 15

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Answer 16

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Answer 17

Ch. 22 - Which element has more nonmetallic character:Cl or...Ch. 22 - Prob. 22.2A Ch. 22 - Prob. 22.3P Ch. 22 - Prob. 22.4A Ch. 22 - Prob. 22.5P Ch. 22 - Look at the location of elements A, B, C, and Din...Ch. 22 - What are the formula and charge of the silicate...Ch. 22 - Suggest a plausible structure for the silicate...Ch. 22 - Prob. 22.9P Ch. 22 - Write balanced net ionic equations for the...

Solution Summary: The author explains how oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electron through covalent bonding.

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