(a) Interpretation: The Lewis acid and the Lewis base should be identified when ammonia reacts with borane to form ammonia borane. Concept introduction: Lewis acid is a chemical substance which can accept an electron pair and Lewis base is a chemical substance which can donate an electron pair.
(a) Interpretation: The Lewis acid and the Lewis base should be identified when ammonia reacts with borane to form ammonia borane. Concept introduction: Lewis acid is a chemical substance which can accept an electron pair and Lewis base is a chemical substance which can donate an electron pair.
Solution Summary: The author explains that Lewis acid and Lewis base should be identified when ammonia reacts with borane to form a chemical substance.
The Lewis acid and the Lewis base should be identified when ammonia reacts with borane to form ammonia borane.
Concept introduction:
Lewis acid is a chemical substance which can accept an electron pair and Lewis base is a chemical substance which can donate an electron pair.
Interpretation Introduction
(b)
Interpretation:
The electron-dot structure for ammonia borane should be drawn. The hybridization of nitrogen and boron and the bond angles should be given.
Concept introduction:
Compound which have second row elements and hydrogen, the second-row elements are bonded to one another in a central core and hydrogens are on the periphery. Compounds which have more than one second row elements, there may be more than one possible electron-dot structure.
[In this question, there are multiple answers to type in a "fill-in-the-blank" fashion - in each case, type in a whole number.] Consider using Slater's Rules to calculate the shielding factor (S) for the last electron in silicon (Si). There will be
electrons with a 0.35 S-multiplier,
electrons with a 0.85 S-multiplier, and
electrons with a 1.00 S-multiplier.
Provide the unknown for the given data.
Draw the Lewis structures of two methanol (CH3OH) molecules and depict hydrogenbonding between them with dashed lines. Show all lone pairs. Provide a thorough analysis to apply concept idea into other problems.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.