(a) Interpretation: The molecular geometry of H 2 Se should be described. Concept introduction: Molecular geometry is the three-dimensional shape which a molecule occupies in space. Molecular geometry of a particular atom is determined by the central atom, groups bonded to it and lone pairs. the shape can be predicted by the Valence Shell Electron Pair Repulsion (VSEPR) theory.
(a) Interpretation: The molecular geometry of H 2 Se should be described. Concept introduction: Molecular geometry is the three-dimensional shape which a molecule occupies in space. Molecular geometry of a particular atom is determined by the central atom, groups bonded to it and lone pairs. the shape can be predicted by the Valence Shell Electron Pair Repulsion (VSEPR) theory.
Solution Summary: The author explains that molecular geometry is the three-dimensional shape which a molecule occupies in space.
The molecular geometry of H2Se should be described.
Concept introduction:
Molecular geometry is the three-dimensional shape which a molecule occupies in space. Molecular geometry of a particular atom is determined by the central atom, groups bonded to it and lone pairs. the shape can be predicted by the Valence Shell Electron Pair Repulsion (VSEPR) theory.
Interpretation Introduction
(b)
Interpretation:
The molecular geometry of AsH3 should be described.
Concept introduction:
Molecular geometry is the three-dimensional shape which a molecule occupies in space. Molecular geometry of a particular atom is determined by the central atom, groups bonded to it and lone pairs. the shape can be predicted by the Valence Shell Electron Pair Repulsion (VSEPR) theory.
Interpretation Introduction
(c)
Interpretation:
The molecular geometry of SiH4 should be described.
Concept introduction:
Molecular geometry is the three-dimensional shape which a molecule occupies in space. Molecular geometry of a particular atom is determined by the central atom, groups bonded to it and lone pairs. the shape can be predicted by the Valence Shell Electron Pair Repulsion (VSEPR) theory.
The decomposition of dinitrogen pentoxide according to the equation:
50°C
2 N2O5(g)
4 NO2(g) + O2(g)
follows first-order kinetics with a rate constant of 0.0065 s-1. If the initial
concentration of N2O5 is 0.275 M, determine:
the final concentration of N2O5 after 180 seconds.
...
Don't used hand raiting
CS2(g) →CS(g) + S(g)
The rate law is Rate = k[CS2] where k = 1.6 × 10−6 s−¹.
S
What is the concentration of CS2 after 5 hours if the initial concentration is 0.25 M?
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