(a) Interpretation: Each binary hydride should be identified as ionic, covalent or interstitial. Concept introduction: The location of each element in the periodic table determines the formula of the hydride it forms. Alkali metals form ionic hydrides and have the formula AH . Transition elements form interstitial hydrides and have no definite stoichiometric formula, AH x . Covalent hydrides are formed by nonmetals and the formula depends on their group in periodic table.
(a) Interpretation: Each binary hydride should be identified as ionic, covalent or interstitial. Concept introduction: The location of each element in the periodic table determines the formula of the hydride it forms. Alkali metals form ionic hydrides and have the formula AH . Transition elements form interstitial hydrides and have no definite stoichiometric formula, AH x . Covalent hydrides are formed by nonmetals and the formula depends on their group in periodic table.
Solution Summary: The author explains that each binary hydride should be identified as ionic, covalent or interstitial.
Definition Definition Elements containing partially filled d-subshell in their ground state configuration. Elements in the d-block of the periodic table receive the last or valence electron in the d-orbital. The groups from IIIB to VIIIB and IB to IIB comprise the d-block elements.
Chapter 22, Problem 22.21CP
Interpretation Introduction
(a)
Interpretation:
Each binary hydride should be identified as ionic, covalent or interstitial.
Concept introduction:
The location of each element in the periodic table determines the formula of the hydride it forms. Alkali metals form ionic hydrides and have the formula AH. Transition elements form interstitial hydrides and have no definite stoichiometric formula, AHx. Covalent hydrides are formed by nonmetals and the formula depends on their group in periodic table.
Interpretation Introduction
(b)
Interpretation:
The oxidation state of hydrogen and the other element in compounds (1), (2) and (3) should be determined.
Concept introduction:
In ionic hydrides, hydrogen is in oxidation state and in other types of hydride, hydrogen is in +1 oxidation state.
1. Show the steps necessary to make 2-methyl-4-nonene using a
Wittig reaction. Start with triphenylphosphine and an alkyl
halide. After that you may use any other organic or inorganic
reagents.
2. Write in the product of this reaction:
CH3
CH₂
(C6H5)₂CuLi
H₂O+
3. Name this compound properly, including stereochemistry.
H₂C
H3C
CH3
OH
4. Show the step(s) necessary to transform the compound on the
left into the acid on the right.
Bri
CH2
5. Write in the product of this
LiAlH4
Br
H₂C
OH
What are the major products of the following reaction? Please provide a detailed explanation and a drawing to show how the reaction proceeds.
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