(a) Interpretation: Each binary hydride should be identified as ionic, covalent or interstitial. Concept introduction: The location of each element in the periodic table determines the formula of the hydride it forms. Alkali metals form ionic hydrides and have the formula AH . Transition elements form interstitial hydrides and have no definite stoichiometric formula, AH x . Covalent hydrides are formed by nonmetals and the formula depends on their group in periodic table.
(a) Interpretation: Each binary hydride should be identified as ionic, covalent or interstitial. Concept introduction: The location of each element in the periodic table determines the formula of the hydride it forms. Alkali metals form ionic hydrides and have the formula AH . Transition elements form interstitial hydrides and have no definite stoichiometric formula, AH x . Covalent hydrides are formed by nonmetals and the formula depends on their group in periodic table.
Solution Summary: The author explains that each binary hydride should be identified as ionic, covalent or interstitial.
Definition Definition Elements containing partially filled d-subshell in their ground state configuration. Elements in the d-block of the periodic table receive the last or valence electron in the d-orbital. The groups from IIIB to VIIIB and IB to IIB comprise the d-block elements.
Chapter 22, Problem 22.21CP
Interpretation Introduction
(a)
Interpretation:
Each binary hydride should be identified as ionic, covalent or interstitial.
Concept introduction:
The location of each element in the periodic table determines the formula of the hydride it forms. Alkali metals form ionic hydrides and have the formula AH. Transition elements form interstitial hydrides and have no definite stoichiometric formula, AHx. Covalent hydrides are formed by nonmetals and the formula depends on their group in periodic table.
Interpretation Introduction
(b)
Interpretation:
The oxidation state of hydrogen and the other element in compounds (1), (2) and (3) should be determined.
Concept introduction:
In ionic hydrides, hydrogen is in oxidation state and in other types of hydride, hydrogen is in +1 oxidation state.
1. Give stereochemical (Fischer projection) formulas for all (but no extras) the
stereoisomers that could theoretically form during the reduction of
a. the carbonyl group of 2-methyl-3--pentanone
b. both carbonyl groups of 2,4-pentanedione (careful!)
2. Predict the products of the reduction of O=CCH2CH2CH2C=O with
a. LiAlH4
b. NaBH4
CH3
OH
Which of the following compounds can be synthesized using one reaction from any alkene, as a major product? If it can be synthesized, propose a route, and you may use any other starting materials, reagents and solvents as needed. If you do not think that it can be synthesized as a major product from an alkene, explain in detail why.
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