Organic Chemistry
11th Edition
ISBN: 9781118133576
Author: T. W. Graham Solomons, Craig Fryhle
Publisher: Wiley, John & Sons, Incorporated
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Chapter 22, Problem 13PP
Interpretation Introduction
Interpretation:
The structure of L-(+)-threose and L-(+)-erythrose is to be represented and the aldotriose, which must be used for the preparation of the above-mentioned compounds in the Kiliani-Fischer synthesis, is to be determined.
Concept Introduction:
▸ The Kiliani-Fischer reaction is used for increasing the number of carbon atoms of an aldose molecule, as a result of the formation of the epimeric aldonic acid.
▸ It is an effective and economic process for the synthesis of monosaccharides by the process of hydrolysis of a cyanohydrin.
▸ Furthermore, it can also be used for the production of epimers of higher aldoses from a lower aldose, that is, a single aldose produces a mixture of two diastereomeric sugars called epimers.
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Identify monomeric and multimeric (di-,tri-meric, for example) saccharides
from this group. If you come across multimeric polypeptides, state the mono-
mers that form these multimers. State the nature of the bond that links two
units together in each case.
(a) Maltose
(b) Trehalose
(c) Lactose
(d) Sucrose
(e) Cellobiose
(f) Agarose
An optically active D-aldopentose (A) produced an optically inactive alditol (B) upon treatment with H2/Pt. When the aldopentose (A) was subjected to a Ruff degradation, D-aldotetrose (C) was generated. The aldotetrose (C) gave an optically active aldaric acid (D) upon oxidation with HNO3. D-aldopentose (A) can be prepared from D-threose by a Killani Fischer synthesis. Propose structure of A through D.
Give me a clear handwritten answer with explanation
Chapter 22 Solutions
Organic Chemistry
Ch. 22 - Prob. 1PPCh. 22 - Prob. 2PPCh. 22 - Prob. 3PPCh. 22 - Prob. 4PPCh. 22 - Prob. 5PPCh. 22 - Prob. 6PPCh. 22 - Prob. 7PPCh. 22 - Prob. 8PPCh. 22 - Practice Problem 22.9 What products would you...Ch. 22 - Prob. 10PP
Ch. 22 - Prob. 11PPCh. 22 - Prob. 12PPCh. 22 - Prob. 13PPCh. 22 - Prob. 14PPCh. 22 - Prob. 15PPCh. 22 - Prob. 16PPCh. 22 - Prob. 17PPCh. 22 - Prob. 18PPCh. 22 - Prob. 19PPCh. 22 - Prob. 20PCh. 22 - Prob. 21PCh. 22 - Prob. 22PCh. 22 - Prob. 23PCh. 22 - Prob. 24PCh. 22 - Prob. 25PCh. 22 - Prob. 26PCh. 22 - Prob. 27PCh. 22 - Prob. 28PCh. 22 - Prob. 29PCh. 22 - Prob. 30PCh. 22 - Prob. 31PCh. 22 - Prob. 32PCh. 22 - Prob. 33PCh. 22 - Prob. 34PCh. 22 - Prob. 35PCh. 22 - Prob. 36PCh. 22 - Prob. 37PCh. 22 - Prob. 38PCh. 22 - Arbutin, a compound that can be isolated from the...Ch. 22 - Prob. 40PCh. 22 - Prob. 41PCh. 22 - Prob. 42PCh. 22 - Prob. 43PCh. 22 - 22.44 The following reaction sequence represents...Ch. 22 - 22.45
The NMR data for the two anomers...Ch. 22 - Shikimic acid is a key biosynthetic intermediate...Ch. 22 - Prob. 1QCh. 22 - Prob. 2QCh. 22 - Give the structural formula of the monosaccharide...Ch. 22 - Prob. 4QCh. 22 - Prob. 5QCh. 22 - Prob. 6QCh. 22 - Prob. 7QCh. 22 - Prob. 8QCh. 22 - Select the reagent needed to perform the following...
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- Aldohexoses A and B both undergo Ruff degradation to give aldopentose C. On treatment with warm nitric acid, aldopentose C gives an optically active aldaric acid. B alsoreacts with warm nitric acid to give an optically active aldaric acid, but A reacts to givean optically inactive aldaric acid. Aldopentose C is degraded to aldotetrose D, whichgives optically active tartaric acid when it is treated with nitric acid. Aldotetrose D isdegraded to (+)@glyceraldehyde. Deduce the structures of sugars A, B, C, and D, and useFigure 23-3 to determine the correct names of these sugars.arrow_forwardWhen the gum of the shrub Sterculia setigera is subjected to acidic hydrolysis, one of the water-soluble components of thehydrolysate is found to be tagatose. The following information is known about tagatose:(1) Molecular formula C6H12O6(2) Undergoes mutarotation.(3) Does not react with bromine water.(4) Reduces Tollens reagent to give d-galactonic acid and d-talonic acid.(5) Methylation of tagatose (using excess CH3 I and Ag2O) followed by acidic hydrolysis gives1,3,4,5-tetra-O-methyltagatose.(a) Draw a Fischer projection structure for the open-chain form of tagatose.(b) Draw the most stable conformation of the most stable cyclic hemiacetal form of tagatosearrow_forwardA D-aldopentose A is oxidized to an optically inactive aldaric acid with HNO3. A is formed by the Kiliani–Fischer synthesis of a D-aldotetrose B, which is also oxidized to an optically inactive aldaric acid with HNO3. What are the structures of A and B?arrow_forward
- 22.46 (a&d only)arrow_forwardCompound A is a D-aldopentose that can be oxidized to an optically inactive aldaric acid B. On Kiliani-Fischer chain extension, A is converted into C and D; C can be oxidized to an optically active aldaric acid E, but D is oxidized to an optically inactive aldaric acid F. What is the structure of compound F? • Use the wedge/hash bond tools to indicate stereochemistry where it exists. You do not have to explicitly draw H atoms. If a group is achiral, do not use wedged or hashed bonds on it. • Show stereochemistry in a meso compound. • Do not include lone pairs in your answer. They will not be considered in the grading.arrow_forwardThere are three (3) vials labeled A, B, and C known to contain the following monosaccharides. All three samples reduce Tollens and Fehling. By oxidation with dilute HNO3 an optically active aldaric acid is obtained for sample A and the remaining two give products without optical activity. When the three samples were subjected to an alkaline medium, it was observed that, after a certain time, samples A and C reached the same value of the specific rotation [α]. Select the RIGHT alternative: (a) Sample A is Galactose. (b) Sample B is Alosa. (c) Samples A and C are not related to each other by an epimerization process. (d) Sample C is Talose. (e) Samples B and C are epimers.arrow_forward
- 4arrow_forwardWill the reduction using NaBH4 of D-glucose and D-galactose give an optically active or inactive compound?Explain why and draw your solution.arrow_forward(1) what reagent is used to convert p-amino phenol to quinone (2) Draw two different kekule's structures for pyrene and under line the more stablearrow_forward
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