Chapter 21, Problem 60A

Interpretation Introduction

Interpretation:

The $\text{-C-O-C-}$ bond between rings in disaccharide sugar needs to be determined.

Concept introduction:

Carbohydrate- Carbohydrates are the naturally occurring organic compound. It consists of carbon, hydrogen, and oxygen. There are aldehyde, ketone, and polyhydroxy groups present. The carbonyl group is present in aldehyde, ketone, and alcohol group present as a polyhydroxy group.

Answer to Problem 60A

Sucrose is a disaccharide, where the $\text{-C-O-C-}$ bond found between rings in disaccharide.

Explanation of Solution

Sucrose is a disaccharide. Sucrose formed by the two monosaccharide, glucose and fructose are connected with $\text{-C-O-C-}$ bond and converted into a disaccharide.

Conclusion

The disaccharide is formed from glucose and fructose, monosaccharide is present in ring form and connect with $\text{-C-O-C-}$ bond and form a disaccharide.