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Concept explainers
(a)
Interpretation:
The reaction of capsaicin, with
Concept introduction:
One of the common reactions of alkene is electrophilic addition reaction. An electrophile attacks the double bond and gives the addition product. When unsaturated
(b)
Interpretation:
The reaction of capsaicin with dilute aqueous
Concept introduction:
In presence of base amides get hydrolyzed. The amide bond
(c)
Interpretation:
The reaction of capsaicin with dilute aqueous
Concept introduction:
Amides can easily be hydrolyzed in presence of dilute acid or bases. Amides upon reaction with dilute aqueous hydrochloric acid get hydrolyzed to form a carboxylic acid and corresponding ammonium salt. Amines can be extracted by hydrolysis of corresponding amides.
(d)
Interpretation:
The reaction of capsaicin with
Concept introduction:
In presence of a catalyst the unsaturated bond can be saturated by addition of hydrogen gas. The hydrogen is added to both carbons of double bond. Capsaicin undergoes hydrogenation reaction with hydrogen in presence of a catalyst.
(e)
Interpretation:
The reaction that occurs when product of part (d) is heated with
Concept introduction:
The amide bond can be hydrolyzed in the presence of base or acid. When the amide bond is hydrolyzed in the presence of base as catalyst, then an amine and carboxylate salt is formed. However, when the amide bond is hydrolyzed in the presence of acid, an ammonium salt and carboxylic acid is formed.
(f)
Interpretation:
The reaction of product of part (b) with
Concept introduction:
The sodium salts of carboxylic acids are used to get compound with higher number of carbon atoms. The sodium salts of carboxylic acids are treated with
(g)
Interpretation:
The reaction of product of part (d) when heated with concentrated aqueous
Concept introduction:
The amide bond can be hydrolyzed in the presence of base or acid. When the amide bond is hydrolyzed in the presence of base as catalyst, then an amine and carboxylate salt is formed. However, when the amide bond is hydrolyzed in the presence of acid, an ammonium salt and carboxylic acid is formed.
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Chapter 21 Solutions
Organic Chemistry Study Guide and Solutions
- In the solid state, oxalic acid occurs as a dihydrate with the formula H2C2O4 C+2H2O. Use this formula to calculate the formula weight of oxalic acid. Use the calculated formula weight and the number of moles (0.00504mol) of oxalic acid in each titrated unknown sample recorded in Table 6.4 to calculate the number of grams of pure oxalic acid dihydrate contained in each titrated unknown sample.arrow_forward1. Consider a pair of elements with 2p and 4p valence orbitals (e.g., N and Se). Draw their (2p and 4p AO's) radial probability plots, and sketch their angular profiles. Then, consider these orbitals from the two atoms forming a homonuclear л-bond. Which element would have a stronger bond, and why? (4 points)arrow_forwardWrite the reaction and show the mechanism of the reaction. Include the mechanism for formation of the NO2+ 2. Explain, using resonance structures, why the meta isomer is formed. Draw possible resonance structures for ortho, meta and para.arrow_forward
- Nonearrow_forward3. A molecular form of "dicarbon", C2, can be generated in gas phase. Its bond dissociation energy has been determined at 599 kJ/mol. Use molecular orbital theory to explain why energy of dissociation for C₂+ is 513 kJ/mol, and that for C2² is 818 kJ/mol. (10 points)arrow_forward9.73 g of lead(IV) chloride contains enough Cl- ions to make ____ g of magnesium chloride.arrow_forward
- 6. a) C2's. Phosphorus pentafluoride PF5 belongs to D3h symmetry group. Draw the structure of the molecule, identify principal axis of rotation and perpendicular (4 points) b) assume that the principal axis of rotation is aligned with z axis, assign symmetry labels (such as a1, b2, etc.) to the following atomic orbitals of the P atom. (character table for this group is included in the Supplemental material). 3s 3pz (6 points) 3dz²arrow_forward2. Construct Lewis-dot structures, and draw VESPR models for the ions listed below. a) SiF5 (4 points) b) IOF4 (4 points)arrow_forward5. Complex anion [AuCl2]¯ belongs to Doh symmetry point group. What is the shape of this ion? (4 points)arrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
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