Starting Out with Java: From Control Structures through Data Structures (4th Edition) (What's New in Computer Science)
4th Edition
ISBN: 9780134787961
Author: Tony Gaddis, Godfrey Muganda
Publisher: PEARSON
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Chapter 21, Problem 19TF
Program Description Answer
The set of all descendants of a node in a binary tree form a subtree rooted at that node.
Hence, the given statement is “False”.
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True or False: The largest element in any non-empty BST always has no right child.
True or False: The smallest element in any non-empty BST always has no right child.
A tree node that has no children is called a
node.
The children of a same parent node are called as
2. Write the code for preorder traversal of a binary tree.
struct node{
int data;
struct node *left, *right;
}
void preorder(node *x) {
}
True or false: A full tree expressed as an array needs around three times less space than a linked node representation of the same tree?
Chapter 21 Solutions
Starting Out with Java: From Control Structures through Data Structures (4th Edition) (What's New in Computer Science)
Ch. 21.1 - Prob. 21.2CPCh. 21.1 - Prob. 21.3CPCh. 21 - Prob. 1MCCh. 21 - Prob. 2MCCh. 21 - Prob. 3MCCh. 21 - Prob. 4MCCh. 21 - Prob. 5MCCh. 21 - Prob. 6MCCh. 21 - Prob. 7MCCh. 21 - Prob. 8MC
Ch. 21 - Prob. 9MCCh. 21 - Prob. 10MCCh. 21 - Prob. 11TFCh. 21 - Prob. 12TFCh. 21 - Prob. 13TFCh. 21 - Prob. 14TFCh. 21 - Prob. 15TFCh. 21 - Prob. 16TFCh. 21 - Prob. 17TFCh. 21 - Prob. 18TFCh. 21 - Prob. 19TFCh. 21 - Prob. 20TFCh. 21 - Prob. 21TFCh. 21 - Prob. 1FTECh. 21 - Prob. 2FTECh. 21 - Prob. 3FTECh. 21 - Prob. 1SACh. 21 - Prob. 2SACh. 21 - Prob. 3SACh. 21 - Prob. 4SACh. 21 - What is a priority queue?Ch. 21 - Prob. 6SACh. 21 - Prob. 7SACh. 21 - Prob. 1AWCh. 21 - Prob. 2AWCh. 21 - Prob. 3AWCh. 21 - Prob. 4AWCh. 21 - Prob. 5AWCh. 21 - Prob. 6AWCh. 21 - Prob. 7AWCh. 21 - Prob. 4PCCh. 21 - Prob. 6PC
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- #ifndef BT_NODE_H#define BT_NODE_H struct btNode{ int data; btNode* left; btNode* right;}; // pre: bst_root is root pointer of a binary search tree (may be 0 for// empty tree) and portArray has the base address of an array large// enough to hold all the data items in the binary search tree// post: The binary search tree has been traversed in-order and the data// values are written (as they are encountered) to portArray in// increasing positional order starting from the first elementvoid portToArrayInOrder(btNode* bst_root, int* portArray);void portToArrayInOrderAux(btNode* bst_root, int* portArray, int& portIndex); // pre: (none)// post: dynamic memory of all the nodes of the tree rooted at root has been// freed up (returned back to heap/freestore) and the tree is now empty// (root pointer contains the null address)void tree_clear(btNode*& root); // pre: (none)// post: # of nodes contained in tree rooted at root is returnedint…arrow_forwardProgramming questions：typedef struct node { int data; struct node *left, *right;}BT;The node structure of the binary tree (BT) is shown above. There is a binary tree T, please complete the function: int degreeone(BT *T) to compute how many degree 1 node in the BT. The T is the root pointer, and the function shoule return the total number of degree 1 node.arrow_forwardC++arrow_forward
- Breadth-first search must be done without recursion. (with iterative)arrow_forwardBinary Search Tree Empirical and Theoretical ResultsPart 1: we need to define a binary search tree data structure. Also, we need to implement the following functions:1. Insert Sorted: BSTREE insert(BSTREE root, int num): root points to a node in a binary search tree; num is a number to be inserted in the tree rooted at “root”. This function returns the root of the modified tree.2. Print Elements: void inorder traversal(BSTREE root, FILE *fp): root points to a node in a binary search tree. This function does not return anything, but prints out, to the file specified, the nodes in the tree rooted at “root” by performing an inorder traversal. Part 2: Test the performance of the designed data structure using theoretical and experimental approaches as follows:1. Dataset 1-Dataset is sorted- Add code to insert the numbers 1...n in that order in an initially empty doubly linked list and a binary search tree.a. Run it on different values of n where :i. n = 20,000ii. n = 50,000iii. n =…arrow_forwardstruct insert_into_bst { // Function takes a constant Book as a parameter, inserts that book indexed by // the book's ISBN into a binary search tree, and returns nothing. void operator()(const Book& book) { // // TO-DO (7) ||| ///// // Write the lines of code to insert the key (book's ISBN) and value // ("book") pair into "my_bst". END-TO-DO (7) | } std::map& my_bst; };arrow_forward
- H.w2: the following figure shows an array representation for a binary tree: L X W E A H M Draw this tree Traverse the tree using Depth-First Traversal and Breadth-First Traversalarrow_forwardGiven the following struct that represents a binary tree: struct Node { int key: Node "parent; Node "left; Node "right; Nodelint k) : key(k), parent(nullptr), left(nullptr), right(nullptr) (I: 1: Write a recursive function that prints out the nodes in a tree stored using the above structure in order to cout. The function prints the depth (root depth is at 0) and key of that node separated by a colon (Example "O: 10\n" for root with key 10). Your function CAN NOT create any local variables and can only use what is passed to the function. Use the below function signature (NOTE: this is not a class method). void inorderAndDepth(Node "node, int depth)arrow_forwardAssume the following node structure used in a binary tree. struct NodeType{ int info; Node Type *right; // points to right child Node Type *left; // points to left child }; Write a function named leafNodeCount that takes a pointer p to a node of a binary tree and returns the number of leaf nodes in the subtree rooted by the node pointed to by p. Edit Format Table |BIU Av 2v T? v || * WP 12pt v Paragraph v O words :::: D.arrow_forward
- Using discriminated union in F#, create a tree type that can be either an empty tree or a tree node of float * tree * treearrow_forwardProgramming language C++ problemarrow_forward4. Complete the fuction definition given below that takes the root node of a tree as a parameter and returns the count of nodes. int count_nodes(Node *root){ // complete the function }arrow_forward
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