Starting Out with Java: From Control Structures through Data Structures (4th Edition) (What's New in Computer Science)
Starting Out with Java: From Control Structures through Data Structures (4th Edition) (What's New in Computer Science)
4th Edition
ISBN: 9780134787961
Author: Tony Gaddis, Godfrey Muganda
Publisher: PEARSON
Expert Solution & Answer
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Chapter 21, Problem 3FTE

Explanation of Solution

Given program code:

//Add 1 to the value in each node of the tree

Void incrementAll(Node tree)

{

    //Call the function to increment the left sub-tree

    incrementAll (tree.left);

    //Call the function to increment the right sub-tree

    incrementAll (tree.right);

    //Increment the value

    tree.Value++;

}

The above program code snippet is used to increment value in each node of the tree.

Error in the program code:

In the above code segment, the function “incrementAll ()” will fail if the node “tree” is equal to “null”. It should be modified using “if” statement.

Corrected code:

The modified code is highlighted below.

//Add 1 to the value in each node of the tree

Void incrementAll(Node tree)

{

    if (tree != null)

    {

//Call the function to increment the left sub-tree

        incrementAll (tree...

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Task: Complete the function getMinDepth (Node *root), the function takes the root of a tree and returns the minimum depth of the tree. int getMinDepth(Node *root){ //write your code here } Constraints: The number of nodes in the tree is in the range [0, 100000]. -1000 <= Node.val <= 1000
What does this part of code do? void addRecord(Node *& head, Node *& tail, string name, double balance){    Node *newNode = new Node;    newNode->name = name;    newNode->balance = balance;    newNode->next = NULL;    newNode->prev = NULL;    // If list is empty, make newNode the first node    if(head == NULL){        head = newNode;        tail = newNode;    }    else{        Node *temp = head;        // Loop through list until temp->next is NULL        while(temp->next != NULL){            temp = temp->next;        }        temp->next = newNode;        newNode->prev = temp;        tail = newNode;    }} /*
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