Starting Out with Java: From Control Structures through Data Structures (4th Edition) (What's New in Computer Science)
Starting Out with Java: From Control Structures through Data Structures (4th Edition) (What's New in Computer Science)
4th Edition
ISBN: 9780134787961
Author: Tony Gaddis, Godfrey Muganda
Publisher: PEARSON
Expert Solution & Answer
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Chapter 21, Problem 3FTE

Explanation of Solution

Given program code:

//Add 1 to the value in each node of the tree

Void incrementAll(Node tree)

{

    //Call the function to increment the left sub-tree

    incrementAll (tree.left);

    //Call the function to increment the right sub-tree

    incrementAll (tree.right);

    //Increment the value

    tree.Value++;

}

The above program code snippet is used to increment value in each node of the tree.

Error in the program code:

In the above code segment, the function “incrementAll ()” will fail if the node “tree” is equal to “null”. It should be modified using “if” statement.

Corrected code:

The modified code is highlighted below.

//Add 1 to the value in each node of the tree

Void incrementAll(Node tree)

{

    if (tree != null)

    {

//Call the function to increment the left sub-tree

        incrementAll (tree...

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Students have asked these similar questions
Task: Complete the function getMinDepth (Node *root), the function takes the root of a tree and returns the minimum depth of the tree. int getMinDepth(Node *root){ //write your code here } Constraints: The number of nodes in the tree is in the range [0, 100000]. -1000 <= Node.val <= 1000
True or False: Any node in a tree can be viewed as being the root of its own tree.
please convert to C languange   #include<bits/stdc++.h>using namespace std; class tree{ //tree node    public:        int data;        tree *left;        tree *right;}; bool hasRootToLeafSum(tree *root, int s){    bool path=false; //declare boolean variable path    //base condition checking    if(root==NULL && s==0)        return true;     s-=root->data; //subtract current root value     //checking whether leaf node reached and remaining sum =0    if(s==0 && root->left==NULL && root->right==NULL)         return true;    //recursively done for both subtrees    if(root->left){//for left subtree        path=path||hasRootToLeafSum(root->left, s);    }    if(root->right){//for right subtree        path=path||hasRootToLeafSum(root->right, s);    }    return path;} tree* newnode(int data){  //creating new nodes    tree* node = (tree*)malloc(sizeof(tree));     node->data = data;     node->left = NULL;     node->right = NULL;…
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