Chapter 20, Problem 53A

(a)

Interpretation Introduction

Interpretation:

The reaction at the copper strip is to be written.

Concept introduction:

The reactions happening in a chemical cell depend on the reduction potential of the half cells.

Answer to Problem 53A

Reaction at copper strip:

$C{u}^{2+}(aq)+2e^{-}\to Cu(s)$

Explanation of Solution

The E⁰ for the above reaction is positive therefore it is more feasible.

(b)

Interpretation Introduction

Interpretation:

The reaction at the magnesium wire is to be written.

Concept introduction:

The reactions happening in a chemical cell depend on the reduction potential of the half cells.

Answer to Problem 53A

Reaction at magnesium wire:

$Mg(s)\to M{g}^{2+}(aq)+2e^{-}$

Explanation of Solution

The E⁰ for the above reaction is positive therefore it is more feasible.

(c)

Interpretation Introduction

Interpretation:

The anode is to be identified.

Concept introduction:

The electrode at which oxidation occurs is the anode.

Answer to Problem 53A

The magnesium wire is the anode.

Explanation of Solution

Since oxidation is occurring at the Mg wire, it is the anode.

(d)

Interpretation Introduction

Interpretation:

The cathode is to be identified.

Concept introduction:

The electrode at which reduction occurs is the cathode.

Answer to Problem 53A

The copper strip is the anode.

Explanation of Solution

Since reduction is occurring at the Cu strip, it is the anode.

(e)

Interpretation Introduction

Interpretation:

The standard cell potential is to be calculated.

Concept introduction:

The standard cell potential is equal to the sum of half cell potentials.

Answer to Problem 53A

The standard cell potential is2.71V.

Explanation of Solution

$\begin{array}{l}E{°}_{reduction}=0.34V\\ E{°}_{oxidation}=2.37V\\ E{°}_{cell}=0.34+2.37\\ E{°}_{cell}=2.71V\end{array}$

The standard cell potential is 2.71V.