a.
Interpretation:
The complete cell reaction for the given cell is to be written.
Concept introduction:
The half reactions when balanced and added make the full cell reaction.
a.
Answer to Problem 81A
The equation for the cell reaction:
Explanation of Solution
Since Sn has less reduction potential than Hg, it will get oxidized resulting in this reaction.
Oxidation half reaction:
Reduction half reaction:
Thus, overall reaction is:
b.
Interpretation:
The substances oxidized and reduced, and the oxidizing an reducing agents are to be identified and mentioned.
Concept introduction:
The substance getting oxidized becomes reducing agent and vice versa.
b.
Answer to Problem 81A
The oxidizing agent is mercury and the reducing agent is tin.
The substance getting oxidized is tin and the substance getting reduced is mercury.
Explanation of Solution
Since Sn has less reduction potential than Hg, it will get oxidized resulting in this reaction.
Oxidation half reaction:
Reduction half reaction:
The deciding factor in this situation is the reduction potentials of both half cell reactions.
c.
Interpretation:
The reactions occurring at the anode and the cathode are to be written in balanced equation.
Concept introduction:
Oxidation occurs at the anode and reduction occurs at the cathode.
c.
Answer to Problem 81A
The equation for anode reaction:
The equation for cathode reaction:
Explanation of Solution
Tin is getting oxidized and oxidation occurs at the anode and mercury gets reduced and reduction occurs at the cathode.
Therefore,
Oxidation half reaction:
(Anode)
Reduction half reaction:
(Cathode)
d.
Interpretation:
The overall potential difference of the cell is to be calculated and found out.
Concept introduction : The cell potential is the sum of the potentials of its oxidation and reduction halves.
d.
Answer to Problem 81A
The potential of the cell is 0.99V.
Explanation of Solution
e.
Interpretation:
The direction of movement of sulphate ions in the salt bridge is to be identified and mentioned.
Concept introduction:
In a salt bridge the positive ions move towards the side with more electrons and vice versa.
e.
Answer to Problem 81A
The sulphate ions will move towards the mercury half cell.
Explanation of Solution
Since mercury is getting reduced there is lack of electrons in mercury half cell so sulphate ions move from the salt bridge to balance the charge.
Chapter 20 Solutions
Chemistry: Matter and Change
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