General, Organic, & Biological Chemistry
3rd Edition
ISBN: 9780073511245
Author: Janice Gorzynski Smith Dr.
Publisher: McGraw-Hill Education
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Chapter 20, Problem 20.72P
Interpretation Introduction
Interpretation:
A segment of the polysaccharide formed by 3 mannose units joined together in 1-4 − β − linkages needs to be drawn.
Concept introduction:
1-4 − β − linkages are formed due to condensation reaction of a hydroxyl group on fourth carbon atom of one sugar with the anomeric first carbon of another sugar. β sign is given due to the position of the bonding hydroxyl group of anomeric carbon atom, which is above the ring.
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MISSED THIS? Read Section 19.9 (Pages 878-881); Watch IWE 19.10
Consider the following reaction:
CH3OH(g)
CO(g) + 2H2(g)
(Note that AG,CH3OH(g) = -162.3 kJ/mol and AG,co(g)=-137.2 kJ/mol.)
Part A
Calculate AG for this reaction at 25 °C under the following conditions:
PCH₂OH
Pco
PH2
0.815 atm
=
0.140 atm
0.170 atm
Express your answer in kilojoules to three significant figures.
Ο ΑΣΦ
AG = -150
Submit
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kJ
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Calculate the free energy change under nonstandard conditions (AGrxn) by using the following relationship:
AGrxn = AGrxn + RTInQ,
AGxn+RTInQ,
where AGxn is the standard free energy change, R is the ideal gas constant, T is the temperature in kelvins, a
is the reaction quotient.
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Identify and provide a brief explanation of Gas Chromatography (GC) within the context of chemical analysis of food. Incorporate the specific application name, provide a concise overview of sample preparation methods, outline instrumental parameters and conditions ultilized, and summarise the outcomes and findings achieved through this analytical approach.
Chapter 20 Solutions
General, Organic, & Biological Chemistry
Ch. 20.1 - Label the hemiacetal carbonthe carbon bonded to...Ch. 20.1 - Prob. 20.2PCh. 20.1 - Prob. 20.3PCh. 20.1 - Prob. 20.4PCh. 20.1 - Prob. 20.5PCh. 20.2 - Prob. 20.6PCh. 20.2 - Prob. 20.7PCh. 20.2 - Prob. 20.8PCh. 20.2 - Prob. 20.9PCh. 20.2 - Prob. 20.10P
Ch. 20.3 - Prob. 20.11PCh. 20.3 - Prob. 20.12PCh. 20.4 - Prob. 20.13PCh. 20.4 - Prob. 20.14PCh. 20.4 - Prob. 20.15PCh. 20.4 - Prob. 20.16PCh. 20.4 - Prob. 20.17PCh. 20.4 - Prob. 20.18PCh. 20.5 - Lactose contains both an acetal and a hemiacetal....Ch. 20.5 - Prob. 20.20PCh. 20.5 - Prob. 20.21PCh. 20.6 - Prob. 20.22PCh. 20.6 - Prob. 20.23PCh. 20.7 - Prob. 20.24PCh. 20.7 - Prob. 20.25PCh. 20.8 - Prob. 20.26PCh. 20 - Prob. 20.27PCh. 20 - Prob. 20.28PCh. 20 - Prob. 20.29PCh. 20 - Prob. 20.30PCh. 20 - Prob. 20.31PCh. 20 - Prob. 20.32PCh. 20 - Prob. 20.33PCh. 20 - Prob. 20.34PCh. 20 - Prob. 20.35PCh. 20 - Prob. 20.36PCh. 20 - Prob. 20.37PCh. 20 - Prob. 20.38PCh. 20 - Prob. 20.39PCh. 20 - Prob. 20.40PCh. 20 - Prob. 20.41PCh. 20 - Prob. 20.42PCh. 20 - Prob. 20.43PCh. 20 - Prob. 20.44PCh. 20 - Prob. 20.45PCh. 20 - Prob. 20.46PCh. 20 - Prob. 20.47PCh. 20 - Prob. 20.48PCh. 20 - Prob. 20.49PCh. 20 - Prob. 20.50PCh. 20 - Prob. 20.51PCh. 20 - Prob. 20.52PCh. 20 - Prob. 20.53PCh. 20 - Prob. 20.54PCh. 20 - Prob. 20.55PCh. 20 - Prob. 20.56PCh. 20 - Prob. 20.57PCh. 20 - Prob. 20.58PCh. 20 - Prob. 20.59PCh. 20 - Prob. 20.60PCh. 20 - Prob. 20.61PCh. 20 - Prob. 20.62PCh. 20 - Prob. 20.63PCh. 20 - Prob. 20.64PCh. 20 - Prob. 20.65PCh. 20 - Prob. 20.66PCh. 20 - Prob. 20.67PCh. 20 - Prob. 20.68PCh. 20 - Prob. 20.69PCh. 20 - Prob. 20.70PCh. 20 - Prob. 20.71PCh. 20 - Prob. 20.72PCh. 20 - Prob. 20.73PCh. 20 - Prob. 20.74PCh. 20 - Prob. 20.75PCh. 20 - Prob. 20.76PCh. 20 - Prob. 20.77PCh. 20 - Prob. 20.78PCh. 20 - Prob. 20.79PCh. 20 - Prob. 20.80PCh. 20 - Prob. 20.81PCh. 20 - Prob. 20.82PCh. 20 - Prob. 20.83PCh. 20 - Prob. 20.84PCh. 20 - Prob. 20.85PCh. 20 - Prob. 20.86PCh. 20 - Prob. 20.87CPCh. 20 - Prob. 20.88CP
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