(a) Interpretation: The glycosidic linkage in cellobiose should be located. Concept Introduction: Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

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Answer 1

Question

Chapter 20.4, Problem 20.17P

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

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Students have asked these similar questions

(i) Which one of the following is a disaccharide : Starch, Maltose, Fructose, Glucose?(ii) What is the difference between fibrous protein and globular protein?(iii) Write the name of vitamin whose deficiency causes bones deformities in children.

(A) Identify the glycosidic bond in the following disaccharide (B) Decide whether the compound is a non reducing or reducing sugar (C) Polysaccharide units are usually bonded together with alpha or beta 1,6 or 1,4 linkages. What linkage is used in the disaccharide shown below?

Arabinoxylan is a copolymer of arabinose and xylose-two five-carbon sugars. A portion of the polysaccharide is shown here. (a) Identify and classify each glycosidic linkage. (b) Based on the structure, do you think arabinoxylan functions as a storage polysaccharide or a structural polysaccharide? Explain your reasoning. HOH,C. OH Но OH OH но но OH Но LO. Но HOH,C HOH2C НО OH OH CH,OH

Answer 2

Question

Chapter 20.4, Problem 20.17P

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

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Answer 3

Question

Chapter 20.4, Problem 20.17P

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

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Answer 4

Question

Chapter 20.4, Problem 20.17P

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

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Answer 5

Chapter 20.4, Problem 20.17P

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

Answer 6

Chapter 20.4, Problem 20.17P

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Answer 7

Chapter 20.4, Problem 20.17P

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Answer 8

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Answer 9

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 20.1 - Label the hemiacetal carbonthe carbon bonded to...Ch. 20.1 - Prob. 20.2P Ch. 20.1 - Prob. 20.3P Ch. 20.1 - Prob. 20.4P Ch. 20.1 - Prob. 20.5P Ch. 20.2 - Prob. 20.6P Ch. 20.2 - Prob. 20.7P Ch. 20.2 - Prob. 20.8P Ch. 20.2 - Prob. 20.9P Ch. 20.2 - Prob. 20.10P

Solution Summary: The author explains that the glycosidic linkage in cellobiose should be located.

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