
Concept explainers
(a)
Interpretation:
Hemiacetal C should be identified and that should be label as either a or β anomer.
Concept Introduction:
Hemi-acetal is a C atom which connected to two different O atoms. One O atom is in alcohol form and the other one connected to another C atom.
Anomer C-Type of C atoms that are not stereo-genic in linear form, but stereo-genic in cyclic form. stereo-genic center can be classified as either a or β. If the -OH group is located upwards, it is β anomer and if -OH group is located downwards it is a anomer.
(b)
Interpretation:
Hemiacetal C should be identified and that should be label as either a or β anomer.
Concept Introduction:
Hemi-acetal is a C atom which connected to two different O atoms. One O atom is in alcohol form and the other one connected to another C atom.
Anomer C-Type of C atoms that are not stereo-genic in linear form, but stereo-genic in cyclic form. stereo-genic center can be classified as either a or β. If the -OH group is located upwards, it is β anomer and if -OH group is located downwards it is a anomer.
(c)
Interpretation:
Hemiacetal C should be identified and that should be label as either a or β anomer.
Concept Introduction:
Hemi-acetal is a C atom which connected to two different O atoms. One O atom is in alcohol form and the other one connected to another C atom.
Anomer C-Type of C atoms that are not stereo-genic in linear form, but stereo-genic in cyclic form. stereo-genic center can be classified as either a or β. If the -OH group is located upwards, it is β anomer and if -OH group is located downwards it is a anomer.

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Chapter 20 Solutions
General, Organic, & Biological Chemistry
- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
