General, Organic, & Biological Chemistry
General, Organic, & Biological Chemistry
3rd Edition
ISBN: 9780073511245
Author: Janice Gorzynski Smith Dr.
Publisher: McGraw-Hill Education
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Chapter 20, Problem 20.45P
Interpretation Introduction

(a)

Interpretation:

The hemiacetal carbon of the given monosaccharide should be identified.

Concept introduction:

When an alcohol and ether group is attached to the same carbon, it is called the hemiacetal carbon.

Interpretation Introduction

(b)

Interpretation:

By identifying the unique features in the anomeric carbon, a or β nature should be decided.

Concept introduction:

Two anomers can be constructed as alpha ( α) ** beta (β), depending on the configurational difference in the anomeric Carbon.

Interpretation Introduction

(c)

Interpretation:

By applying necessary amendments to the anomeric carbon of the given structure, α anomer should be derived.

Concept introduction:

In a cyclic simple sugar 2 anomers exists depending on the bond arrangement on anomeric carbon.

Interpretation Introduction

(d)

Interpretation:

A stereoisomer should be derived by making necessary changes to the C2position of the given monosaccharide.

Concept introduction:

When a carbon atom has 4 different entities bound to it, it is called as a stereo center.

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6. Consider the following exothermic reaction below. 2Cu2+(aq) +41 (aq)2Cul(s) + 12(aq) a. If Cul is added, there will be a shift left/shift right/no shift (circle one). b. If Cu2+ is added, there will be a shift left/shift right/no shift (circle one). c. If a solution of AgNO3 is added, there will be a shift left/shift right/no shift (circle one). d. If the solvent hexane (C6H14) is added, there will be a shift left/shift right/no shift (circle one). Hint: one of the reaction species is more soluble in hexane than in water. e. If the reaction is cooled, there will be a shift left/shift right/no shift (circle one). f. Which of the changes above will change the equilibrium constant, K?
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Chapter 20 Solutions

General, Organic, & Biological Chemistry

Ch. 20.3 - Prob. 20.11PCh. 20.3 - Prob. 20.12PCh. 20.4 - Prob. 20.13PCh. 20.4 - Prob. 20.14PCh. 20.4 - Prob. 20.15PCh. 20.4 - Prob. 20.16PCh. 20.4 - Prob. 20.17PCh. 20.4 - Prob. 20.18PCh. 20.5 - Lactose contains both an acetal and a hemiacetal....Ch. 20.5 - Prob. 20.20PCh. 20.5 - Prob. 20.21PCh. 20.6 - Prob. 20.22PCh. 20.6 - Prob. 20.23PCh. 20.7 - Prob. 20.24PCh. 20.7 - Prob. 20.25PCh. 20.8 - Prob. 20.26PCh. 20 - Prob. 20.27PCh. 20 - Prob. 20.28PCh. 20 - Prob. 20.29PCh. 20 - Prob. 20.30PCh. 20 - Prob. 20.31PCh. 20 - Prob. 20.32PCh. 20 - Prob. 20.33PCh. 20 - Prob. 20.34PCh. 20 - Prob. 20.35PCh. 20 - Prob. 20.36PCh. 20 - Prob. 20.37PCh. 20 - Prob. 20.38PCh. 20 - Prob. 20.39PCh. 20 - Prob. 20.40PCh. 20 - Prob. 20.41PCh. 20 - Prob. 20.42PCh. 20 - Prob. 20.43PCh. 20 - Prob. 20.44PCh. 20 - Prob. 20.45PCh. 20 - Prob. 20.46PCh. 20 - Prob. 20.47PCh. 20 - Prob. 20.48PCh. 20 - Prob. 20.49PCh. 20 - Prob. 20.50PCh. 20 - Prob. 20.51PCh. 20 - Prob. 20.52PCh. 20 - Prob. 20.53PCh. 20 - Prob. 20.54PCh. 20 - Prob. 20.55PCh. 20 - Prob. 20.56PCh. 20 - Prob. 20.57PCh. 20 - Prob. 20.58PCh. 20 - Prob. 20.59PCh. 20 - Prob. 20.60PCh. 20 - Prob. 20.61PCh. 20 - Prob. 20.62PCh. 20 - Prob. 20.63PCh. 20 - Prob. 20.64PCh. 20 - Prob. 20.65PCh. 20 - Prob. 20.66PCh. 20 - Prob. 20.67PCh. 20 - Prob. 20.68PCh. 20 - Prob. 20.69PCh. 20 - Prob. 20.70PCh. 20 - Prob. 20.71PCh. 20 - Prob. 20.72PCh. 20 - Prob. 20.73PCh. 20 - Prob. 20.74PCh. 20 - Prob. 20.75PCh. 20 - Prob. 20.76PCh. 20 - Prob. 20.77PCh. 20 - Prob. 20.78PCh. 20 - Prob. 20.79PCh. 20 - Prob. 20.80PCh. 20 - Prob. 20.81PCh. 20 - Prob. 20.82PCh. 20 - Prob. 20.83PCh. 20 - Prob. 20.84PCh. 20 - Prob. 20.85PCh. 20 - Prob. 20.86PCh. 20 - Prob. 20.87CPCh. 20 - Prob. 20.88CP
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