A 2.25 mole sample of an ideal gas with
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Thermodynamics, Statistical Thermodynamics, & Kinetics
- Benzoic acid, C6H5COOH, is a common standard used in bomb calorimeters, which maintain a constant volume. If 1.20 g of benzoic acid gives off 31, 723 J of energy when burned in the presence of excess oxygen and in a water bath having a temperature of 24.6 C, calculate q, w, H, and U for the reaction.arrow_forwardThe Dieterici equation of state for one mole of gas is p=RTe-aVRTV-b Where a and b are constants determined experimentally. For NH3g, a = 10.91 atm. L2 and b = 0.0401 L. Plot the pressure of the gas as the volume of 1.00 mol of NH3g expands from 22.4 L to 50.0 L at 273 K, and numerically determine the work done by the gas by measuring the area under the curve.arrow_forwardWhat is the finaltemperature of0.122 mole ofmonatomic ideal gas that performs 75J of work adiabatically if the initial temperature is 235C?arrow_forward
- a) Suppose that attractions are the dominant interaction between gas molecules, and the equation of state is p = nRT/V – n2a/V2. Determine the work (W(non-ideal gas)) of reversible, isothermal expansion of such a gas from initial volume V (initial) = 20.0 L to final volume V(final) = 40.0 L if n = 2.00 mol, T = 300 K, and a = 3.621 atm-L2/mol2. Watch your units. (b) Determine the work (W(ideal gas) of reversible, isothermal expansion of an ideal gas from initial volume V (initial) = 20.0 L to final volume V(final) = 40.0 L if n = 2.00 mol and T = 300 K. (c) Show the difference W(non-ideal) – W(ideal). If all your calculations are done correctly, this result shows you the effect of attractive interaction between gas particles on the work done by the system.arrow_forwardTwo moles of an ideal gas are expanded reversibly and isothermally at 0 °C from 1 atm. Calculate the final volume (in L) occupied by the gas if the heat absorbed during the process is 750 cal.arrow_forwardFive moles of monatomic ideal gas enter the abc cycle and during a complete cycle 600 J of heat is removed from the gas. Process ab is under constant pressure and process bc is increasing at constant volume takes place at pressure. The temperatures of points a and b are Ta= 3°C and Tb= 63°C. What is the work in the ca process?arrow_forward
- Knowing that the molar heat capacity at constant pressure of CO₂ has the form Cp,m = (a + b + c/T²) J mol-¹K-¹, where a= 44.22, b= 8.79 x 10-³ K-¹, and c= -8.62 x 105 K 2,calculate how much heat can absorb 1.5 moles of this gas when the temperature is increased from 25°C to 150°C. NOTE: Give your answer in kJ mol-1arrow_forwardF-2 8. A 3.50 mole sample of an ideal gas with Cv= 3R/2 undergoes reversible expansion. The initial temperature and pressure are T1 = 310 K and P1 = 15.2 bar. The final pressure is P2 = 1.45 bar. Calculate ΔU in kJ for this process. (First calculate T2) Please show all steps.arrow_forwardAssuming ideal gas behavior, calculate ΔH Assuming ideal gas behavior, calculate q Assuming ideal gas behavior, calculate ΔU w =−2.48×104 Jarrow_forward
- How would I calculate work(w), heat(q), energy change(ΔU), enthalpy change(ΔH), and entropy (ΔS) from a sample of 10.0 L of oxygen, originally at 90.18 K and 0.500 atm, is brought to a temperature of 475.0 K and 1.00 atm. Assuming that the oxygen behaves as an ideal gas and that it’s constant pressure heat capacity is given by Cp= 29.96+4.18 x 10^-3 T - 1.75 x 10^5 / T^2arrow_forward1. Real-life heat Capacity is temperature dependent. Consider the formation of water vapor H2(g)+( )O2(g) → H20(g) The heat capacities Cp(T) for each of the reactants and the product is given by Cp-a+bT+CT2 where the constants a, b and c depend on the substance. The above equation is valid from 298 K to 2,000 K. a. The units of a, b and c are . ? b. Calculate AH given (298 K)=-60kCal. Express your answers in terms of a, b, c for the reactants and products (aH2, bH2 --) (Answers choices for part b) дН (T) — — 6оCal O AH (T) = -60kCal + (aH,0 – aĦ, – ļa0.) (T – 298K) + 4 (b#,0 – bH, – įbo.) (T² – 298° K²) – (CH,0 – CH, – țco.) (+ - ) AH (T) = (an,0 – an, – 40,) (T – 298K) + (bn,0 – bn, – bo;) (T² – 298° K²) – (cH,0 – CH, - co,) (- K) Ο ΔΗ (T)ε = -60kCal – (aH,0 – a#, - }a0.) (T – 298K) – | (bH,0 – bH, - bo.) (T² – 298° K²) + (cH,0 – CH, - co.) ( - K)arrow_forwardP3C.5 Use values of standard enthalpies of formation, standard entropies, and standard heat capacities available from tables in the Resource section to calculate the standard enthalpy and entropy changes at 298 K and 398 K for the reaction CO2(g) + H2(g) → CO(g) + H₂O(g). Assume that the heat capacities are constant over the temperature range involved.arrow_forward
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